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20 Apr 2020, 11:01
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
95% (00:40) correct
5%
(00:56)
wrong
based on 1146
sessions
History
Date
Time
Result
Not Attempted Yet
\(m ⊕ p =n\)
\(n ⊕ r =m \)
\(n ⊕ q =q \)
\(p ⊕ q =p \)
\(q ⊕ p =r \)
If the relations shown hold for the operation ⊕ and the numbers m, n, p, q, and r, then \([(m⊕p)⊕ q]⊕ p =\)
(A) m
(B) n
(C) p
(D) q
(E) r
PS45430.02
\(n ⊕ r =m \)
\(n ⊕ q =q \)
\(p ⊕ q =p \)
\(q ⊕ p =r \)
If the relations shown hold for the operation ⊕ and the numbers m, n, p, q, and r, then \([(m⊕p)⊕ q]⊕ p =\)
(A) m
(B) n
(C) p
(D) q
(E) r
PS45430.02
28 Apr 2020, 09:42
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Bookmarks
gmatt1476
I. \(m ⊕ p =n\)
II. \(n ⊕ r =m \)
III. \(n ⊕ q =q \)
IV. \(p ⊕ q =p \)
V. \(q ⊕ p =r \)
If the relations shown hold for the operation ⊕ and the numbers m, n, p, q, and r, then \([(m⊕p)⊕ q]⊕ p =\)
(A) m
(B) n
(C) p
(D) q
(E) r
From statement I, we can write: [(m ⊕ p) ⊕ q] ⊕ p = [(n) ⊕ q] ⊕ p = [n ⊕ q] ⊕ p
From statement III, we can write: [n ⊕ q] ⊕ p = [q] ⊕ p = q ⊕ p
From statement V, we can write: q ⊕ p = r
Answer: E
Cheers,
Brent
General Discussion
20 Apr 2020, 14:55
Kudos
Bookmarks
gmatt1476
\(m ⊕ p =n\)
\(n ⊕ r =m \)
\(n ⊕ q =q \)
\(p ⊕ q =p \)
\(q ⊕ p =r \)
If the relations shown hold for the operation ⊕ and the numbers m, n, p, q, and r, then \([(m⊕p)⊕ q]⊕ p =\)
(A) m
(B) n
(C) p
(D) q
(E) r
PS45430.02
\([(m⊕p)⊕ q]⊕ p = [n⊕q]⊕p= [q]⊕p= r\)
Answer (E).
