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Apr 2808:00 AM PDT
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15 Aug 2016, 04:03
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
84% (01:25) correct
16%
(01:11)
wrong
based on 100
sessions
History
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If the set S is composed of the following numbers {99, 100, 100, 105, 106, 116, 123}, which of the following is largest?
A. The average (arithmetic mean) of set S
B. The median of set S
C. The mode of set S
D. The range of set S
E. The standard deviation of set S
A. The average (arithmetic mean) of set S
B. The median of set S
C. The mode of set S
D. The range of set S
E. The standard deviation of set S
15 Aug 2016, 05:25
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Bunuel
Time consuming question...
A) 99, 100, 100, 105, 106, 116, 123 = 749 and its mean is 749/7 = 107.
B) The list is of 7 numbers and median is 105.
C) Mode is number of repetition of a number in the list , here it is 100.
D) Range = Max value - min value = 123 -99 = 24.
E) SD = square root of (sum of ( mean of series - number)^2 ) / n => sq root (64+49+49+4+1+676)/7 = sq rt ( 893/7) = sq rt ( 127) < 100
IMO option A is correct answer..
OA please..will correct if I missed anything..
15 Aug 2016, 19:13
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Eyeballing through the set and the given options, the only true contenders are average and median. The values are around 100-110 so the answer must be close to that.
Range can be discarded as it is nowhere near 100 or 110.
Standard deviation can be discarded without any calculation. Standard deviation is the square root of the average of deviation of each value from the mean. The key word is square root. For standard deviation to be anywhere close to 100-110, the value inside the root needs to quite large and there is no way that can happen for the given set of values.
Median is the middle value. Since, we have 7 terms, median will be the 4th value -> 105.
Average:
Assume average is 100.
Get the "differential" of each term from the assumed average of 100 and add them up.
-1 + 0 + 0 + 5 + 6 + 16 + 23 = 49.
Since there is an extra 49, it needs to be evenly distributed among the 7 members.
49 / 7 = 7.
Add 7 back to the assumed average.
Actual average = 100 + 7 = 107.
107 > 105 or Average > Median.
Answer (A).
Range can be discarded as it is nowhere near 100 or 110.
Standard deviation can be discarded without any calculation. Standard deviation is the square root of the average of deviation of each value from the mean. The key word is square root. For standard deviation to be anywhere close to 100-110, the value inside the root needs to quite large and there is no way that can happen for the given set of values.
Median is the middle value. Since, we have 7 terms, median will be the 4th value -> 105.
Average:
Assume average is 100.
Get the "differential" of each term from the assumed average of 100 and add them up.
-1 + 0 + 0 + 5 + 6 + 16 + 23 = 49.
Since there is an extra 49, it needs to be evenly distributed among the 7 members.
49 / 7 = 7.
Add 7 back to the assumed average.
Actual average = 100 + 7 = 107.
107 > 105 or Average > Median.
Answer (A).
