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18 Jan 2018, 03:10
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
76% (01:07) correct
24%
(01:35)
wrong
based on 143
sessions
History
Date
Time
Result
Not Attempted Yet
If the volume of the cube above is 64 cubic centimeters, what is the shortest distance, in centimeters, from point A to point B?
A. \(4\sqrt{2}\)
B. \(4\sqrt{3}\)
C. \(4\sqrt{6}\)
D. \(8\sqrt{2}\)
E. \(8\sqrt{3}\)
Attachment:
2018-01-18_1409.png [ 3.79 KiB | Viewed 8630 times ]
18 Jan 2018, 04:48
Kudos
Bookmarks
Bunuel
We'll go for Precise since there is an explicit rule that addresses this question.
This doesn't come up too often, but the diagonal of a cube has length \(\sqrt{3}a\), where a is the length of the side.
Since the volume is 64, then the length of each side is 4 (as 4^3=64) so the length of the diagonal is \(4\sqrt{3}\)
(B) is our answer.
Note - to calculate this, you need to use the Pythagorean theorem twice - once to find the diagonal of the side and the second time to find the diagonal of the cube.
The general equation for the diagonal of a rectangular solid is \(\sqrt{a^2+b^2+c^2}\) where a,b,c are the lengths of the sides.
18 Jan 2018, 07:52
Kudos
Bookmarks
Bunuel
Sides of the cube is 4 cm
Diagonal of a cube is \(a\sqrt{3}\) = \(4\sqrt{3}\) answer will be (B)
