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Given: x ＞ 0 Since we're told that x is POSITIVE, we can safely take x² ＜ x and divide both sides by x to get: x ＜ 1 REPHRASED target question: Is x ＜ 1 ?

Statement 1: 0.1 ＜ x ＜ 0.4 If x is BETWEEN 0.1 and 0.4, then we can be certain that x ＜ 1 Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT

Statement 2: x³ ＜ x² If x is POSITIVE, then we know that x² is also POSITIVE This means we can safely take x³ ＜ x² and divide both sides by x² to get x ＜ 1 Aha! This is exactly what our REPHRASED target question is asking! Since we can answer the REPHRASED target question with certainty, statement 2 is SUFFICIENT

[quote="smartyman"]If x ＞ 0, is x^2 ＜ x ? (1) 0.1 ＜ x ＜ 0.4 (2) x^3 ＜ x^2

lets take x^2-x <0 --We can rewrite it as: x(x-1)<0, if we plot it on number line , we will get a range between {0-1}(0 and 1 not included) that will satisfy x^2-x <0. so any solution having range 0-1 will satisfy the given equation.

A. Suff.

B.x^2(x-1)<0---if plot in a number line , x can only have value between {0-1}(excluding 0 and 1) and can have x<0 as solution..as in the question stem it is given as x can take only positive value.only possible range is {0-1}.this range satisfy x^2-x <0 also .so suff.