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 Q51  V47
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Re: If x and y are integers and x>y, then what is the value of x-y? [#permalink]
Expert Reply
mangamma wrote:
If x and y are integers and x>y, then what is the value of x-y?

(1) 0.5 < ((x−y)^2)/5 < 1

(2) -1 < 2y < 2 < 2x < 5


If you let k = x - y, and multiply the inequality in Statement 1 throughout by 5, you get

2.5 < k^2 < 5

and since k is a positive integer, k must be 2.

From Statement 2, if y is an integer, and -1 < 2y < 2, dividing by 2 we find -1/2 < y < 1, and y must be 0. If x is an integer and 2 < 2x < 5, similarly 1 < x < 2.5, and x must be 2. So we can find both x and y from Statement 2 and answer any question about them.

So the answer is D.
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Re: If x and y are integers and x>y, then what is the value of x-y? [#permalink]
Quote:
(1) 0.5 < ((x−y)^2)/5 < 1

Simplifying
5/2 < (x-y)^2 < 5
Taking square root
\(\sqrt{2.5}\) < |x-y| < \(\sqrt{5}\)
taking approx readings
1.05 < |x-y| < 2.1
x-y could be -2 or 2 as c-y is positive, hence x-y = 2
Sufficient


Quote:
(2) -1 < 2y < 2 < 2x < 5

dividing by 2
-0.5 < y < 1< x < 2.5
y = 0, x = 2
x-y = 2
Sufficient

D is correct
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Re: If x and y are integers and x>y, then what is the value of x-y? [#permalink]
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Re: If x and y are integers and x>y, then what is the value of x-y? [#permalink]
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