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# If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x

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Manager
Joined: 09 Feb 2013
Posts: 121

Kudos [?]: 1147 [1], given: 17

If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x [#permalink]

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15 Feb 2013, 12:01
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15% (low)

Question Stats:

81% (01:16) correct 19% (01:58) wrong based on 137 sessions

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If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x could be

A. 16/5
B. 17/5
C. 4
D. 30/7
E. 31/7
[Reveal] Spoiler: OA

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Last edited by Bunuel on 16 Feb 2013, 03:52, edited 1 time in total.
Edited the question.

Kudos [?]: 1147 [1], given: 17

Manager
Status: Waiting
Joined: 11 Dec 2012
Posts: 53

Kudos [?]: 57 [1], given: 144

Location: Bahrain
Concentration: Healthcare, General Management
GMAT 1: 640 Q49 V24
GMAT 2: 720 Q49 V40
WE: Sales (Other)
Re: If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x [#permalink]

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29 Mar 2013, 10:29
1
KUDOS
VeritasPrepKarishma wrote:

The median is the middle number once all the numbers are arranged in increasing/decreasing order.
We see that
11/3 = 3.something,
28/9 = 3.something
21/5 = 4.something
9/2 = 4.something

So x should greater than the smallest two numbers and smaller than the greatest two numbers. We can see that x = 4 is possible. (First look at the simplest option or the middle option since options are usually arranged in increasing/decreasing order)

The median could be some number such as 4.01 or 3.99, in that we would have to test answer choices too ? Am I right ?

Kudos [?]: 57 [1], given: 144

SVP
Joined: 05 Jul 2006
Posts: 1751

Kudos [?]: 432 [1], given: 49

Re: If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x [#permalink]

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29 Mar 2013, 10:59
1
KUDOS
emmak wrote:
If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x could be

A. 16/5
B. 17/5
C. 4
D. 30/7
E. 31/7

step 1

get all set members expressed in terms of a common denominator , i.e. 90

thus the set becomes (405/90 , 330/90 , 280/90 , 378/90 , 90x /90)

so 90x is the median of set (405,330,280,378)
reorder set (405 , 378,330,280) for 90x to be median of the set it has to be between 378 and 330

looking at number choices
d,e are excluded as 7 is no a factor of 90 , and then we are left with A,B,C

A - 16/5*90 = 288
B = 17/5*90 = 306
C = 90*4 = 360

Obviously then , C it is

Kudos [?]: 432 [1], given: 49

Veritas Prep GMAT Instructor
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Kudos [?]: 17400 [0], given: 232

Location: Pune, India
Re: If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x [#permalink]

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15 Feb 2013, 19:20
emmak wrote:
If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x could be

16/5

17/5

4

30/7

31/7

The median is the middle number once all the numbers are arranged in increasing/decreasing order.
We see that
11/3 = 3.something,
28/9 = 3.something
21/5 = 4.something
9/2 = 4.something

So x should greater than the smallest two numbers and smaller than the greatest two numbers. We can see that x = 4 is possible. (First look at the simplest option or the middle option since options are usually arranged in increasing/decreasing order)
_________________

Karishma
Veritas Prep | GMAT Instructor
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Kudos [?]: 17400 [0], given: 232 Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7677 Kudos [?]: 17400 [0], given: 232 Location: Pune, India Re: If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x [#permalink] ### Show Tags 30 Mar 2013, 03:40 jainpiyushjain wrote: VeritasPrepKarishma wrote: The median is the middle number once all the numbers are arranged in increasing/decreasing order. We see that 11/3 = 3.something, 28/9 = 3.something 21/5 = 4.something 9/2 = 4.something So x should greater than the smallest two numbers and smaller than the greatest two numbers. We can see that x = 4 is possible. (First look at the simplest option or the middle option since options are usually arranged in increasing/decreasing order) Answer (C) The median could be some number such as 4.01 or 3.99, in that we would have to test answer choices too ? Am I right ? Yes, x could be 3.99, 4.01 etc but x could be 4 too. The question says 'x could be', which means there are various possible values of x but only one value is given in the five options. Since we see that 4 is already there and x can certainly be 4, it means we don't need to test any other options because they cannot be the value of x. After all, PS questions have only one correct answer. _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Kudos [?]: 17400 [0], given: 232

Intern
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Re: If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x [#permalink]

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01 Apr 2013, 07:48
emmak wrote:
If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x could be

A. 16/5
B. 17/5
C. 4
D. 30/7
E. 31/7

$$9/2 = 4.5$$
$$11/3= 3.66$$
$$28/9 = 3.13$$
$$21/5 = 4.2$$

Since the set has 5 numbers the median has to be the middle value
Arranging the number in ascending order we get 3.13, 3.66, 4.2, 4.5. Now for x to be the median of the given set, x has to lie between 3.66 and 4.2.
Only one option satisfies the condition i.e x =4

Kudos [?]: 29 [0], given: 6

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Re: If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x [#permalink]

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09 Jul 2014, 07:40
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Re: If x is the median of the set {9/2, 11/3, 28/9, 21/5, x}, x   [#permalink] 09 Jul 2014, 07:40
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