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Joined: 18 Feb 2005
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If x/y = 2/3, then (x  y)/x?
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21 Oct 2005, 01:42
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87% (00:46) correct 13% (01:20) wrong based on 375 sessions
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If \(\frac{x}{y} = \frac{2}{3}\), then \(\frac{x  y}{x}\)? A. 1/2 B. 1/3 C. 1/3 D. 1/2 E. 5/2
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Re: If x/y = 2/3, then (x  y)/x?
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17 Sep 2013, 19:17
njss750 wrote: If x/y =2/3, then (xy)/x?
A. 1/2 B. 1/3 C. 1/3 D. 1/2 E. 5/2 x/y=2/3 > y/x=3/2. \(\frac{xy}{x}=1\frac{y}{x}=1\frac{3}{2}=\frac{1}{2}\). Answer: A.
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Re: If x/y = 2/3, then (x  y)/x?
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21 Oct 2005, 01:54
njss750 wrote: x/y =2/3, then (xy)/x? 1/2, 1/3, 1/3, 1/2, 5/2 Since this was in the last few probs of OG, thot that x/y could also be interpreted as x=2 and y=3 and therefore x/y can be equal to 2/3. OG proved me wrong, but is this a theoretical possibility?
we have this law of fraction:
a/b=c/d= (ac)/(bd)
x/y=2/3 > x/2=y/3= (xy)/(23)=(xy)/(1) > (xy)/x= 1/2



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Re: If x/y = 2/3, then (x  y)/x?
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21 Oct 2005, 01:55
hik, i thought too complicatedly ....you're right, ywilfred!



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Re: If x/y = 2/3, then (x  y)/x?
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17 Sep 2013, 19:02
laxieqv wrote: njss750 wrote: x/y =2/3, then (xy)/x? 1/2, 1/3, 1/3, 1/2, 5/2 Since this was in the last few probs of OG, thot that x/y could also be interpreted as x=2 and y=3 and therefore x/y can be equal to 2/3. OG proved me wrong, but is this a theoretical possibility? we have this law of fraction: a/b=c/d= (ac)/(bd) x/y=2/3 > x/2=y/3= (xy)/(23)=(xy)/(1) > (xy)/x= 1/2 will you please explain this rule i couldn't find it anywhere on the internet? also i am not familiar with it either i have solved it like this:x/y=2/3 xy/x=x/xy/x 12/3=32/3 so the answer is 1/3............. am i right?? :s



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Re: If x/y = 2/3, then (x  y)/x?
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17 Sep 2013, 19:24
x/y=2/3, then y/x=3/2. (xy)/x = x/xy/x = 13/2 = 1/2



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Re: If x/y = 2/3, then (x  y)/x?
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18 Sep 2013, 10:52
i got it!!! thanks guys!!!!



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Re: If x/y = 2/3, then (x  y)/x?
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19 Sep 2013, 03:49
I solved it like this...
x/y = 2/3 so x = 2 and y = 3 substitute and get the answer 1/2



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Re: If x/y = 2/3, then (x  y)/x?
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21 Nov 2013, 19:59
I'm still confused. Where does the 1 come from?



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Re: If x/y = 2/3, then (x  y)/x?
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21 Nov 2013, 21:32
sdlucas wrote: I'm still confused. Where does the 1 come from? You separate out the numerator. \(\frac{(xy)}{x} = \frac{x}{x}  \frac{y}{x} = 1  \frac{y}{x} = 1  \frac{3}{2} = \frac{1}{2}\)
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Re: If x/y = 2/3, then (x  y)/x?
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19 Apr 2016, 16:12
did i get lucky? or can this be a correct approach.
I cross multiplied to get 3x=2y. I then divided by 3 to get 2/3y and just plugged that into where ever x was



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Re: If x/y = 2/3, then (x  y)/x?
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19 Apr 2016, 22:12
ross14 wrote: did i get lucky? or can this be a correct approach.
I cross multiplied to get 3x=2y. I then divided by 3 to get 2/3y and just plugged that into where ever x was Yes, the approach is fine. You are eliminating one variable, bringing it all in terms of a single variable and then cancelling it off to get a value.
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Re: If x/y = 2/3, then (x  y)/x?
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29 Oct 2017, 11:15
njss750 wrote: If x/y =2/3, then (xy)/x?
A. 1/2 B. 1/3 C. 1/3 D. 1/2 E. 5/2 Replace x = 2 & y = 3 So, \(\frac{(xy)}{x} = \frac{2  3}{2} = \frac{1}{2}\) Hence, answer will be (A) \(\frac{1}{2}\)
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Re: If x/y = 2/3, then (x  y)/x?
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15 Sep 2019, 03:11
njss750 wrote: If x/y =2/3, then (xy)/x?
A. 1/2 B. 1/3 C. 1/3 D. 1/2 E. 5/2 Given: x/y =2/3 Asked: (xy)/x=? \(\frac{x}{y} =\frac{2}{3}\) \(\frac{xy}{x} = \frac{1}{2}\) IMO A



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Re: If x/y = 2/3, then (x  y)/x?
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12 Dec 2019, 18:11
(x/y)  (y/y)  = (x/y) 2/3  1  = 2/3 1/2



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Re: If x/y = 2/3, then (x  y)/x?
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01 Jan 2020, 19:43
njss750 wrote: If \(\frac{x}{y} = \frac{2}{3}\), then \(\frac{x  y}{x}\)?
A. 1/2 B. 1/3 C. 1/3 D. 1/2 E. 5/2 Crossmultiplying, we have: 3X = 2Y Thus, we can let X = 2 and Y = 3, so we have: (2  3)/2 = 1/2 Alternate Solution: (XY)/X = X/X  Y/X = 1  Y/X Since X/Y = 2/3, Y/X = 3/2, so 1  Y/X = 1  3/2 = 1/2. Answer: A
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Re: If x/y = 2/3, then (x  y)/x?
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01 Jan 2020, 19:43






