Summer is Coming! Join the Game of Timers Competition to Win Epic Prizes. Registration is Open. Game starts Mon July 1st.

 It is currently 20 Jul 2019, 04:49 ### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # If xy > 0, does (x - 1)(y - 1) = 1?

Author Message
TAGS:

### Hide Tags

Math Expert V
Joined: 02 Sep 2009
Posts: 56303
If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

5
31 00:00

Difficulty:   35% (medium)

Question Stats: 70% (01:36) correct 30% (02:00) wrong based on 1047 sessions

### HideShow timer Statistics The Official Guide For GMAT® Quantitative Review, 2ND Edition

If xy > 0, does (x - 1)(y - 1) = 1?

(1) x + y = xy
(2) x = y

Data Sufficiency
Question: 83
Category: Algebra First- and second-degree equations
Page: 158
Difficulty: 600

GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!

_________________
Math Expert V
Joined: 02 Sep 2009
Posts: 56303
Re: If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

2
8
SOLUTION

If xy > 0, does (x - 1)(y - 1) = 1?

$$xy>0$$ means that either both $$x$$ and $$y$$ are positive or both are negative (so neither of unknowns equals to zero: $$x\neq{0}$$ and $$y\neq{0}$$).

Question: is $$(x-1)(y-1)=1$$? --> is $$xy-x-y+1=1$$? is $$x+y=xy$$?

(1) x + y = xy --> directly gives YES answer to the question. Sufficient.

(2) x = y --> question becomes: is $$x+x=x^2$$? --> is $$x(x-2)=0$$? --> is $$x=0$$ or $$x=2$$? --> as given that $$x\neq{0}$$, then the question becomes is $$x=2$$? We don't know that, hence this statement is not sufficient.

_________________
##### General Discussion
Director  Joined: 25 Apr 2012
Posts: 668
Location: India
GPA: 3.21
Re: If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

1
Bunuel wrote:

If xy > 0, does (x - 1)(y - 1) = 1?

(1) x + y = xy
(2) x = y

]

Sol: given xy> 0 means booths x and y are of same sign.let us solve the given expression we get xy -(x+y) +1

St1: x+y=xy so putting these values in the exp we get xy-xy+1 or1 so st 1 is sufficient

St2 let's put these value in the statement so we get (y-1)^2 or y^2+2y-1=0

So if y=-2 then yes expression equals 1 but if y=2 then no

So st1 is sufficient therefore ans A

600 level is okay
_________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”
Intern  Joined: 30 Jan 2014
Posts: 17
Re: If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

1
If xy > 0, does (x - 1)(y - 1) = 1?

(1) x + y = xy
(2) x = y

xy>0 means that X=0 or y=0

The question ask us if $$(x - 1)(y - 1) = 1$$
Lets fix it up: $$xy-x-y-1=1$$ or $$xy=x+y$$

St(1) is exacty it. Sufficient
St tells us that x=y. Not helping us much.

ans is A
_________________
Please +1 KUDO if my post helps. Thank you.
Intern  Joined: 18 Apr 2015
Posts: 16
Re: If xy > 0 does (x-1)(y-1)=1 ?  [#permalink]

### Show Tags

1
Bunnel,

Option B turns out to be x=0 or x=2.X cannot be equal to zero but we can use x=2 right.In that case we will get (x-1)(y-1)=1
e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 2943
Re: If xy > 0 does (x-1)(y-1)=1 ?  [#permalink]

### Show Tags

2
1
kirtivardhan wrote:
Bunnel,

Option B turns out to be x=0 or x=2.X cannot be equal to zero but we can use x=2 right.In that case we will get (x-1)(y-1)=1

Dear kirtivardhan

Your question tells me that you analyzed St. 2 in one of the following two ways. I'll list them both here and discuss the error in them.

Way 1- You did your analysis of St. 2 as follows:

"Put x = y in x + y = xy
=> $$2x = x^2$$
Upon solving, x = 0 or x = 2"

The error a student who analyses St. 2 in this way does is that he is not considering the equation x = y alone (which is the only piece of info that St. 2 gives) but instead has mistakenly carried over information from St. 1 (x + y = xy) into his analysis of St. 2.

Way 2- You did your analysis of St. 2 as follows:

"Given that x = y
We need to find if $$(x-1)^2 = 1$$?
That is, if $$(x-1)^2 - 1 = 0$$ or (x-1-1)(x-1+1) = 0
That is, x(x-2) = 0
That is, x = 0 or x = 2

We're given that xy > 0. This means, x cannot be EQUAL TO zero. So, x = 2"

The error a student who analyses St. 2 in this way does is that he has used the equation $$(x-1)^2 = 1$$ as a FACT, not as something to be verified

____________

The correct analysis of St. 2 would be as under:

From the question statement, we know that x and y have same sign and both are not equal to zero

From St. 2, x = y

Using this, we've to determine if (x-1)(y-1) = 1? That is, if $$(x-1)^2 = 1$$? That is, if x(x-2) = 0

That is, we need to determine if x = 0 or x = 2.

We know that x cannot be equal to 0

So, we need to determine if x = 2. If x = 2, the equation in the question will hold true. For other values of x, the equation in the question will not hold true.

Since we don't know if x = 2 or not, St. 2 is insufficient to arrive at a unique answer for the given question.

Hope this discussion helped! Regards, Japinder
_________________
Intern  Joined: 18 Apr 2015
Posts: 16
Re: If xy > 0 does (x-1)(y-1)=1 ?  [#permalink]

### Show Tags

Thanks Japinder,

You mean to say that we plugged option b in the question asked and we got x=0 and x=2.If x would have been mentioned to be 2 somehow then option b would have been suff.

I am making sense?

In short ,what we are trying to do is we are plugging an option in to the question asked and checking whether the result is there in the fact

Regards
e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 2943
Re: If xy > 0 does (x-1)(y-1)=1 ?  [#permalink]

### Show Tags

kirtivardhan wrote:
Thanks Japinder,

You mean to say that we plugged option b in the question asked and we got x=0 and x=2.If x would have been mentioned to be 2 somehow then option b would have been suff.

I am making sense?

In short ,what we are trying to do is we are plugging an option in to the question asked and checking whether the result is there in the fact

Regards

Dear kirtivardhan

Yes, you're absolutely right in your first statement. If we were given, either in the question statement or in St. 2 itself that x = 2, then Option B would have been sufficient.

To answer your last statement, let me reiterate what we are trying to do here in Analysis of St. 2:

1. Info given in Question statement: xy > 0. This is a FACT

2. Info given in St. 2: x = y. This is also a FACT

Using these 2 facts, we need to confirm if (x-1)(y-1) = 1? This is the QUESTION.

By using Facts 1 and 2 to simplify the question, we saw that the answer to this question is YES, if x = 2 and NO, if x has some other value.

Hope this clarification helped! Japinder
_________________
Manager  Joined: 18 Aug 2014
Posts: 113
Location: Hong Kong
Schools: Mannheim
Re: If xy > 0 does (x-1)(y-1)=1 ?  [#permalink]

### Show Tags

Bunuel wrote:
guytree wrote:
I am bit sceptic to post this. But I wanted to check if this approach is right.

From the question we know that X and Y both are greater than 0.

In the statement 2 we could use simple plug-ins. If x=y=2 then (x-1)(y-1)=1. However, if x=y=3 then (x-1)(y-1) is not equal to 1.

I would greatly appreciate if you let me understand any loopholes in this approach.

Cheers

If $$xy>0$$ does $$(x-1)(y-1)=1$$?
(1) $$x + y = xy$$
(2) $$x=y$$

$$xy>0$$ means that either both $$x$$ and $$y$$ are positive or both are negative (so neither of unknowns equals to zero: $$x\neq{0}$$ and $$y\neq{0}$$).

Question: is $$(x-1)(y-1)=1$$? --> is $$xy-x-y+1=1$$? is $$x+y=xy$$?

(1) $$x+y=xy$$ --> directly gives us the answer YES. Sufficient.

(2) $$x=y$$ --> question becomes: is $$x+x=x^2$$? --> is $$x(x-2)=0$$? --> is $$x=0$$ or $$x=2$$? --> as given that $$x\neq{0}$$, then the question becomes is $$x=2$$? We don't know that, hence this statement is not sufficient.

Hi Bunuel,

I cannot find any values that represent xy = x+y
Can you provide some explanation?
e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 2943
Re: If xy > 0 does (x-1)(y-1)=1 ?  [#permalink]

### Show Tags

LaxAvenger wrote:
Bunuel wrote:
If $$xy>0$$ does $$(x-1)(y-1)=1$$?
(1) $$x + y = xy$$
(2) $$x=y$$

$$xy>0$$ means that either both $$x$$ and $$y$$ are positive or both are negative (so neither of unknowns equals to zero: $$x\neq{0}$$ and $$y\neq{0}$$).

Question: is $$(x-1)(y-1)=1$$? --> is $$xy-x-y+1=1$$? is $$x+y=xy$$?

(1) $$x+y=xy$$ --> directly gives us the answer YES. Sufficient.

(2) $$x=y$$ --> question becomes: is $$x+x=x^2$$? --> is $$x(x-2)=0$$? --> is $$x=0$$ or $$x=2$$? --> as given that $$x\neq{0}$$, then the question becomes is $$x=2$$? We don't know that, hence this statement is not sufficient.

Hi Bunuel,

I cannot find any values that represent xy = x+y
Can you provide some explanation?

LaxAvenger
xy = x+y

So, xy - x = y
=> x(y-1) = y
=> $$x = \frac{y}{(y-1)}$$

From this equation, you can find a number of (x,y) pairs.

Example, when y = 2, x = 2
When y = 3, x = 3/2 etc.

Please note that you're not told that x and y are integers. So, you should not assume it.

Hope this helped! Japinder
_________________
SVP  B
Joined: 06 Nov 2014
Posts: 1877
Re: If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

1
If xy > 0, does (x - 1)(y - 1) = 1?
One way to think of this is, are (x-1) and (y-1) reciprocals? If that is true,
y - 1 = 1/(x - 1)

(1) x + y = xy
x = xy - y => x = y (x - 1) => (x/(x-1)) = y
This can be plugged into the original equation:
( (x/(x-1) ) - 1 = (1/(x - 1) ) => multiply 1 by (x - 1) to get a common denominator => (x - (x - 1) )/ (x - 1) =(1/(x-1))
(x - x + 1)/(x - 1) = (1/(x-1))
1/(x-1) = 1/(x-1)
Sufficient.
(2) x = y
It's probably easier to try a number. For instance x = y = 8
y - 1 = 8-1 = 7
1/(x - 1) = 1/(8 - 1) = 1/7

But if x = y = 2
y - 1 = 2 - 1 = 1
1/(x - 1) = 1 (2-1) = 1
Not sufficient.
A
Manager  B
Joined: 26 Mar 2017
Posts: 114
Re: If xy > 0 does (x-1)(y-1)=1 ?  [#permalink]

### Show Tags

jakolik wrote:
Hi,

The question is:
(x-1)(y-1)=1 or xy-y-x+1=1 or xy=y+x

Thus first statement is sufficient.
Second statement x=y
x^2=2x which is not sufficient to answer the question.

So the right answer should be A. Are you sure the OA is C?

regards,
Jack

hey just a question, why can we not divide both sides by x to get x=2

I know its wrong but could someone pls let me know why it is wrong ?
_________________
I hate long and complicated explanations!
e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 2943
Re: If xy > 0 does (x-1)(y-1)=1 ?  [#permalink]

### Show Tags

daviddaviddavid wrote:
jakolik wrote:
Hi,

The question is:
(x-1)(y-1)=1 or xy-y-x+1=1 or xy=y+x

Thus first statement is sufficient.
Second statement x=y
x^2=2x which is not sufficient to answer the question.

So the right answer should be A. Are you sure the OA is C?

regards,
Jack

hey just a question, why can we not divide both sides by x to get x=2

I know its wrong but could someone pls let me know why it is wrong ?

Hey,

If we do not whether the variable x is greater than zero or not, we cannot divide both sides by x and get x = 2.

$$x^2 = 2x$$
$$x^2 -2x = 0$$
$$x(x-2) = 0$$
Therefore the value of x can be 0 or 2.

If you divide $$x^2 = 2x$$ by $$x$$ on both sides, you are assuming that x is not equal to 0 and thus this division would make sense: $$\frac{x^2}{x} = \frac{2x}{x}$$ .

If $$x = 0$$ then, $$\frac{x^2}{0} = \frac{2x}{0}$$ is not valid as such. Hence, if one does not know whether x is 0 or non-zero, we take all the terms to the left-hand side of the equation and then solve for the value of x.

Thanks,
Saquib
Quant Expert
e-GMAT
_________________
Target Test Prep Representative D
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 6968
Location: United States (CA)
Re: If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

1
Bunuel wrote:

If xy > 0, does (x - 1)(y - 1) = 1?

(1) x + y = xy
(2) x = y

We can re-express the question as:

Does xy - x - y + 1 = 1 ?

Does xy = x + y ?

Statement One Alone:

x + y = xy

We see that statement one answers the question.

Statement Two Alone:

x = y

Knowing that x = y, is not sufficient to answer the question. If x = y = 2, then (2 - 1)(2 - 1) = 1; however, if x = y = 1, then (1 - 1)(1 - 1) does not does equal 1.

_________________

# Scott Woodbury-Stewart

Founder and CEO

Scott@TargetTestPrep.com

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

CEO  V
Joined: 12 Sep 2015
Posts: 3852
Re: If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

Top Contributor
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

If xy > 0, does (x - 1)(y - 1) = 1?

(1) x + y = xy
(2) x = y

Given: xy > 0

Target question: Does (x - 1)(y - 1) = 1?

This is a good candidate for rephrasing the target question
Take the equation: (x - 1)(y - 1) = 1
Use FOIL to expand the left side to get: xy - x - y + 1 = 1
Subtract 1 from both sides to get: xy - x - y = 0

REPHRASED target question: Does xy - x - y = 0?

Statement 1: x + y = xy
Take the REPHRASED target question and replace xy with x+y to get: Does (x + y) - x - y = 0?
Simplify the left side to get: Does 0 = 0?
Great! The answer to the REPHRASED target question is YES, it IS the case that xy - x - y = 0
Since we can answer the REPHRASED target question with certainty, statement 1 is SUFFICIENT

Statement 2: x = y
There are several values of x and y that satisfy statement 2. Here are two:
Case a: x = 2 and y = 2. In this case, the equation xy - x - y = 0 becomes (2)(2) - 2 - 2 = 0, which works!
So, the answer to the REPHRASED target question is YES, it IS the case that xy - x - y = 0

Case b: x = 1 and y = 1. In this case, the equation xy - x - y = 0 becomes (1)(1) - 1 - 1 = 0, which does NOT work.
So, the answer to the REPHRASED target question is NO, it is NOT the case that xy - x - y = 0

Since we cannot answer the REPHRASED target question with certainty, statement 2 is NOT SUFFICIENT

Cheers,
Brent

RELATED VIDEO FROM OUR COURSE

_________________
VP  G
Joined: 09 Mar 2018
Posts: 1002
Location: India
Re: If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

If xy > 0, does (x - 1)(y - 1) = 1?

(1) x + y = xy
(2) x = y

ALWAYS solve the given question

xy - x - y + 1 = 1
xy = x+y

from 1) this is equal to the question, Sufficient

from 2) Not sufficient at x=y=3

x=y=2, sufficient

A
_________________
If you notice any discrepancy in my reasoning, please let me know. Lets improve together.

Quote which i can relate to.
Many of life's failures happen with people who do not realize how close they were to success when they gave up.
Intern  B
Joined: 14 Mar 2017
Posts: 24
Location: United States (MD)
GPA: 2.9
WE: Science (Other)
Re: If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

Bunuel wrote:
SOLUTION

If xy > 0, does (x - 1)(y - 1) = 1?

$$xy>0$$ means that either both $$x$$ and $$y$$ are positive or both are negative (so neither of unknowns equals to zero: $$x\neq{0}$$ and $$y\neq{0}$$).

Question: is $$(x-1)(y-1)=1$$? --> is $$xy-x-y+1=1$$? is $$x+y=xy$$?

(1) x + y = xy --> directly gives YES answer to the question. Sufficient.

(2) x = y --> question becomes: is $$x+x=x^2$$? --> is $$x(x-2)=0$$? --> is $$x=0$$ or $$x=2$$? --> as given that $$x\neq{0}$$, then the question becomes is $$x=2$$? We don't know that, hence this statement is not sufficient.

Hey Bunuel!

When would tautological information come into play? Statement 1, gives no new information. It just restates the information that can already be found in the prompt question.

Magoosh keeps drilling home the idea that a statement providing no new information is considered insufficient. This has burned me several times on OG questions and causes me to get a simple question wrong. Maybe I'm just not understanding the appropriate situation as to when to use the tautology idea?

I completely understand why your given explanation is the correct answer, but Magoosh rules keep replaying in my head making me want to mark Statement 1 as insufficient because of its redundancy.

Question:
Is $$(x-1)(y-1)=1$$? ----> Is $$xy - x - y + 1 = 1$$ ? ----> Is $$x + y = xy$$?

(1) $$x + y = xy$$ <---- Redundant?
_________________
"What is my purpose?"
"You pass butter."
"Oh my god..."
"Yeah, welcome to the club, pal."
Target Test Prep Representative D
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 6968
Location: United States (CA)
If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

duchessjs wrote:
Bunuel wrote:
SOLUTION

If xy > 0, does (x - 1)(y - 1) = 1?

$$xy>0$$ means that either both $$x$$ and $$y$$ are positive or both are negative (so neither of unknowns equals to zero: $$x\neq{0}$$ and $$y\neq{0}$$).

Question: is $$(x-1)(y-1)=1$$? --> is $$xy-x-y+1=1$$? is $$x+y=xy$$?

(1) x + y = xy --> directly gives YES answer to the question. Sufficient.

(2) x = y --> question becomes: is $$x+x=x^2$$? --> is $$x(x-2)=0$$? --> is $$x=0$$ or $$x=2$$? --> as given that $$x\neq{0}$$, then the question becomes is $$x=2$$? We don't know that, hence this statement is not sufficient.

Hey Bunuel!

When would tautological information come into play? Statement 1, gives no new information. It just restates the information that can already be found in the prompt question.

Magoosh keeps drilling home the idea that a statement providing no new information is considered insufficient. This has burned me several times on OG questions and causes me to get a simple question wrong. Maybe I'm just not understanding the appropriate situation as to when to use the tautology idea?

I completely understand why your given explanation is the correct answer, but Magoosh rules keep replaying in my head making me want to mark Statement 1 as insufficient because of its redundancy.

Question:
Is $$(x-1)(y-1)=1$$? ----> Is $$xy - x - y + 1 = 1$$ ? ----> Is $$x + y = xy$$?

(1) $$x + y = xy$$ <---- Redundant?

Hi duchessjs,

Remember, you need to understand that you are working not with two statements but rather with a question and a statement right?

So before discussing this question, let me provide you with an example:

Me : “John, do you want to go to the movies”

John: “Yes, I want to go to the movies”

Notice that John was able to answer the question by REPEATING what I asked him right?

So in this particular problem, the question is:

Is x + y = xy?

Statement one says: YES, x + y = xy

Thus, statement one is sufficient to answer the question.
_________________

# Scott Woodbury-Stewart

Founder and CEO

Scott@TargetTestPrep.com

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Intern  B
Joined: 06 May 2019
Posts: 12
Location: India
Concentration: General Management, Marketing
Re: If xy > 0, does (x - 1)(y - 1) = 1?  [#permalink]

### Show Tags

If xy > 0, does (x - 1)(y - 1) = 1

Thus,
x and y both can be pos or neg but, x!=0

1)x + y = xy

Product of 2 numbers= sum of rwo numbers

eg: 2+2=2*2

Suff

2) x=y
(x-1)^2 --can be anything---Not suff Re: If xy > 0, does (x - 1)(y - 1) = 1?   [#permalink] 02 Jul 2019, 15:03
Display posts from previous: Sort by

# If xy > 0, does (x - 1)(y - 1) = 1?  