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If xy^2 = 12 and xy = 4, then x =
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01 May 2018, 04:23
Question Stats:
85% (00:58) correct 15% (01:53) wrong based on 66 sessions
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Re: If xy^2 = 12 and xy = 4, then x =
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01 May 2018, 04:46
Bunuel wrote: If \(xy^2 = 12\) and \(xy = 4\), then x =
A. 1
B. 2
C. \(\sqrt{3}\)
D. \(\frac{2}{3}\)
E. \(\frac{4}{3}\) \(xy^2 = 12\) and \(xy = 4\) now replace \(xy = 4\) in \(y*xy\) = 12 y = 3 Replacing y in \(xy\)= 12 X = \(\frac{4}{3}\) Option E



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Re: If xy^2 = 12 and xy = 4, then x =
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01 May 2018, 04:51
Bunuel wrote: If \(xy^2 = 12\) and \(xy = 4\), then x =
A. 1
B. 2
C. \(\sqrt{3}\)
D. \(\frac{2}{3}\)
E. \(\frac{4}{3}\) Given : \(xy^2 = 12\) or \(xy*y = 12\) (I) & \(xy = 4\)(II) Using I and II \(4y = 12\) \(y = 3\) Therefore , \(x (3)^2 = 12\) \(x = \frac{12}{9}\) \(x = \frac{4}{3}\) (E)
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If xy^2 = 12 and xy = 4, then x =
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02 May 2018, 07:13
Bunuel wrote: If \(xy^2 = 12\) and \(xy = 4\), then x =
A. 1
B. 2
C. \(\sqrt{3}\)
D. \(\frac{2}{3}\)
E. \(\frac{4}{3}\) \(xy^2 = 12\) and \(xy=4\) \(x*y*y = 12\), i.e., \((x*y)*y=12\) \(4*y=12\) \(y=3\) \(x=?\) \(xy=4\), and \(y=3\) \(x*3=4\) \(x =\frac{4}{3}\) Answer E



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Re: If xy^2 = 12 and xy = 4, then x =
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02 May 2018, 09:27
Bunuel wrote: If \(xy^2 = 12\) and \(xy = 4\), then x =
A. 1
B. 2
C. \(\sqrt{3}\)
D. \(\frac{2}{3}\)
E. \(\frac{4}{3}\) Let’s first establish that both x and y must be positive. Since xy^2 = 12, we see that x must be positive. And since xy = 4, we see that y must also be positive. Dividing the first equation by the second, we have: y = 3 Substituting y = 3 into the second equation, we have: x(3) = 4 x = 4/3 Alternate Solution: Let’s rewrite the first equation as: x(xy) = 12 We are given that xy = 9, so we can substitute: x(9) = 12 x = 12/9 = 4/3 Answer: E
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Re: If xy^2 = 12 and xy = 4, then x =
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20 Aug 2018, 02:04
Bunuel wrote: If \(xy^2 = 12\) and \(xy = 4\), then x =
A. 1
B. 2
C. \(\sqrt{3}\)
D. \(\frac{2}{3}\)
E. \(\frac{4}{3}\) 1.divide: \(xy^2 = 12\) / \(xy = 4\)y=3 2. substitute: x=4/3 => E



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Re: If xy^2 = 12 and xy = 4, then x =
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20 Aug 2018, 05:55
Bunuel wrote: If \(xy^2 = 12\) and \(xy = 4\), then x =
A. 1
B. 2
C. \(\sqrt{3}\)
D. \(\frac{2}{3}\)
E. \(\frac{4}{3}\) \(y = \frac{xy^2}{xy}\) So, \(y = \frac{12}{4}\) Or, \(y = 3\) We know that \(xy^2 = 12\) Or, \(9x = 12\) Or, \(x = \frac{4}{3}\), Hence Answer must be (E)
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Re: If xy^2 = 12 and xy = 4, then x =
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20 Aug 2018, 08:10
\(xy^2 = 12\) \(xy*y = 12\) \(4y = 12\) \(y=3\) so \(3x=4\) \(x=\frac{4}{3}\)
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Re: If xy^2 = 12 and xy = 4, then x = &nbs
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