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B
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Difficulty:
45%
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Question Stats:
73% (02:08) correct
27%
(02:16)
wrong
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If xy = 3(x + 1) + y; and, x and y are integers, x could be any of the following values except:
A. 7
B. 5
C. 4
D. 3
E. 2
A. 7
B. 5
C. 4
D. 3
E. 2
24 Mar 2024, 04:51
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Lodz697
If xy = 3(x + 1) + y; and, x and y are integers, x could be any of the following values except:
A. 7
B. 5
C. 4
D. 3
E. 2
What's the best way to solve a problem like this?
A. 7
B. 5
C. 4
D. 3
E. 2
What's the best way to solve a problem like this?
You can use the method shown here. Or do the following:
There are several ways to solve this question through algebraic manipulations. You can use the method shown here. Or do the following:
Essentially, our goal is to arrive at an equation of the form \(x = expression \ with \ y \ only\) or \(y = expression \ with \ x \ only\).
\(xy = 3(x + 1) + y\)
\(xy -y= 3(x + 1)\)
\(y(x-1) = 3x + 3\)
\(y=\frac{3x + 3}{x-1}\)
\(y=\frac{3x -3 + 3 + 3}{x-1}\)
\(y=\frac{3x -3 }{x-1}+ \frac{3+3 }{x-1}\)
\(x=3+ \frac{6}{x-1}\)
Answer: B.
Oppenheimer1945
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Schools: INSEAD '26 (S) ISB '27 (D) IIMB '26 (A) IIMA '26 (A) HEC '26 LBS '26 IESE '27 Fuqua '27 Tepper '27
GMAT Focus 1: 645 Q90 V76 DI80
Posts: 827
07 Feb 2024, 10:36
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xy - 3x - y = 3
xy - 3x - y + 3 = 6
(x - 1)(y - 3) = 6
(1, 6) (-1, -6) (6, 1) (-6, -1) (2, 3) (3, 2) (-2, -3) (-3, -2)
x - 1 = 1, -1, 6, -6, 2, 3, -2, -3
x = 2, 0, 7, -5, 3, 4, -1, -2
xy - 3x - y + 3 = 6
(x - 1)(y - 3) = 6
(1, 6) (-1, -6) (6, 1) (-6, -1) (2, 3) (3, 2) (-2, -3) (-3, -2)
x - 1 = 1, -1, 6, -6, 2, 3, -2, -3
x = 2, 0, 7, -5, 3, 4, -1, -2
