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Bunuel
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CounterSniper
Bunuel
In 1970 there were 8,902 women stockbrokers in the United States. By 1978 the number had increased to 19,947. Approximately what was the percent increase?

(A) 45%
(B) 125%
(C) 145%
(D) 150%
(E) 225%

% increase =\(\frac{(19947-8902) * 100}{8902}\)
= \(\frac{11905}{8902 * 100}\)
~\(\frac{12000 *100}{9000}\)
< 130%
~ 125 %
Hey Counter Sniper
i get it that you were trying to round it up to the nearest integer for the answer but (19947-8902 doesn't equal to 11905).
thank you
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I think you should try avoid calculations:

So you know that in 1970 the number of Womens were 8,902.

If the increase was 100% it should be near 18,000 (try to think 9,000x2=18,000, since 8,902 it's close to 9,000) .

If the increase was 150% (9,000x2+ 4,500) the number of Womens would be 22,500

Since 145% is realy near to 150% it can only be option B

:)
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Hello from the GMAT Club BumpBot!

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