Bunuel wrote:

In 1999, Diana read 10 English books and 7 French books. In 2000, she reads twice as many French books as English books. If 60% of the books that she read during the two years were French, how many books did she read in 2000?

A. 16

B. 26

C. 32

D. 39

E. 48

Priyanka8793 , belated welcome and nice solution! +1

Use answer choicesFrench:English books during the year 2,000 = 2x:1x

Total of ratio parts: 3x.

The answer must be a multiple of 3Eliminate A, B, C

Try D) 39 books read during year 2000

3x = 39, so x, multiplier, = 13

# of French books: 2x = 26

# of English books: x = 13

Two-year total of all books?

English: 13 + 10 = 23

French: 26 + 7 =

33Overall: 23 + 33 =

46French/Total should = \(\frac{3}{5}\)

\(\frac{33}{46}\). Stop. That fraction cannot equal \(\frac{3}{5}\)

If unsure, check. No need to divide.

-- estimate: \(\frac{3}{5}\) of 45 = 27 French

-- or multiply (46 * 0.6) = 27.6 French

In answer D, French = 33. Too great.

By POE, the Answer is

Check? E) 48 total books in year 2000

3x = 48, so x = 16

French in 2000: 2x = 32

English in 2000: 1x = 16

Total E: 16 + 10 = 26

Total F: 32 + 7 =

39 Overall total: (26 + 39) =

65\(\frac{39}{65} = \frac{3}{5} = 60\) percent

That's a match.

Answer

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