Bunuel wrote:
In a certain corporation, there are 300 male employees and 100 female employees. It is known that 20% of the male employees have advanced degrees and 40% of the females have advanced degrees. If one of the 400 employees is chosen at random, what is the probability this employee has an advanced degree or is female?
A. 1/20
B. 1/10
C. 1/5
D. 2/5
E. 3/4
Kudos for a correct solution.
Since 20% of the male employees have advanced degrees, 0.2 x 300 = 60 male employees have advanced degrees and 300 - 60 = 240 male employees do not have advanced degrees.
Since 40% of the female employees have advanced degrees, 0.4 x 100 = 40 female employees have advanced degrees and 100 - 40 = 60 female employees do not have advanced degrees.
So, 60 + 40 = 100 employees have an advanced degree.
Thus, the probability of selecting an employee who is female or has an advanced degree is:
P(women) + P(advanced) - P(both)
100/400 + 100/400 - 40/400
160/400 = 16/40 = 2/5
Answer: D
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