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08 Jun 2016, 17:02
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
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Question Stats:
57% (02:11) correct
43%
(01:31)
wrong
based on 171
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In a certain school, teachers who lecture English and Spanish are there. If 2 teachers are selected randomly, what is the probability that at least one teacher selected lectures Spanish?
1) The ratio of Spanish teachers’ number to English teachers’ number is 3 to 1.
2) The sum of Spanish teachers’ number and English teachers’ number is less than 20.
*An answer will be posted in 2 days.
1) The ratio of Spanish teachers’ number to English teachers’ number is 3 to 1.
2) The sum of Spanish teachers’ number and English teachers’ number is less than 20.
*An answer will be posted in 2 days.
08 Jun 2016, 19:17
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MathRevolution
In a certain school, teachers who lecture English and Spanish are there. If 2 teachers are selected randomly, what is the probability that at least one teacher selected lectures Spanish?
1) The ratio of Spanish teachers’ number to English teachers’ number is 3 to 1.
2) The sum of Spanish teachers’ number and English teachers’ number is less than 20.
*An answer will be posted in 2 days.
1) The ratio of Spanish teachers’ number to English teachers’ number is 3 to 1.
2) The sum of Spanish teachers’ number and English teachers’ number is less than 20.
*An answer will be posted in 2 days.
2 teachers are selected, so we require to know the numbers of each to know the probability..
1) The ratio of Spanish teachers’ number to English teachers’ number is 3 to 1.
Important- you can find probability of picking one teacher but not 2 techer as it will vary depending on the number..
if there are 8.. 6 spanish and 2 English.... ans = 6/8*5/7
if there are 4.. 3 spanish and 1 English.... ans = 3/4*2/4
different answers
Insuff
2) The sum of Spanish teachers’ number and English teachers’ number is less than 20.
nothing about individual number of teachers in each language
Insuff..
Combined..
still teachers can be 4, 8, 12, or 16..
so different answers possible
Insuff
E
10 Jun 2016, 22:59
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If we modify the original condition and the question, there are two variables (E and S). In order to match the number of variables and the number of equations, we need 2 equations. Hence, there is high chance that the correct answer is C. Using the condition 1) and the condition 2), since (E,S)=(2,6),(3,9),(4,12), the answer is not unique and the conditions are not sufficient. Thus, the correct answer is E.
- Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
- Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.
