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In a classroom with 6 girls, the average height is x centimeters. If

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In a classroom with 6 girls, the average height is x centimeters. If  [#permalink]

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In a classroom with 6 girls, the average height is x centimeters. If Jenelle joins the class, the average height will be x−1 centimeters. How tall, in centimeters, is Jenelle?

A. x
B. x − 1
C. x − 6
D. x − 7
E. x − 8

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Re: In a classroom with 6 girls, the average height is x centimeters. If  [#permalink]

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New post 11 Mar 2018, 23:16
Bunuel wrote:
In a classroom with 6 girls, the average height is x centimeters. If Jenelle joins the class, the average height will be x−1 centimeters. How tall, in centimeters, is Jenelle?

A. x
B. x − 1
C. x − 6
D. x − 7
E. x − 8


6girls avg = x

total sum = 6x

now \(\frac{6x+ J}{7}\) = x-1

7x-7 = 6x+j

J= x-7
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Re: In a classroom with 6 girls, the average height is x centimeters. If  [#permalink]

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New post 12 Mar 2018, 00:32
Bunuel wrote:
In a classroom with 6 girls, the average height is x centimeters. If Jenelle joins the class, the average height will be x−1 centimeters. How tall, in centimeters, is Jenelle?

A. x
B. x − 1
C. x − 6
D. x − 7
E. x − 8



There are 7 girls in the classroom with the inclusion of Jenelle, and the average
height of the class was x centimeters when Jenelle was not there.

Now, Jenelle would have to be 7 centimeters less than the class average
if the new average height of the class is x-1 centimeters.

Therefore, Jennele's height is x-7(Option D)
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Re: In a classroom with 6 girls, the average height is x centimeters. If  [#permalink]

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New post 12 Mar 2018, 10:33
Bunuel wrote:
In a classroom with 6 girls, the average height is x centimeters. If Jenelle joins the class, the average height will be x−1 centimeters. How tall, in centimeters, is Jenelle?

A. x
B. x − 1
C. x − 6
D. x − 7
E. x − 8


\(6x + j = 7( x - 1)\)

Or, \(6x + j = 7x - 7\)

Or, \(j = x - 7\) , Answer will be (D)
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In a classroom with 6 girls, the average height is x centimeters. If  [#permalink]

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New post 12 Mar 2018, 15:25
Given \(\frac{S}{6}\) = x centimeters-> \(S = 6x\)

\(\frac{Jenelle + S}{6 + 1} = x - 1\) -> \(J + S = 7x - 7\)

Substitute \(S = 6x\) into second equation and you are left with \(J + 6x = 7x - 7\). Simply for J and you left with \(J = x - 7\).

Answer D.
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Re: In a classroom with 6 girls, the average height is x centimeters. If  [#permalink]

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New post 13 Mar 2018, 16:02
Bunuel wrote:
In a classroom with 6 girls, the average height is x centimeters. If Jenelle joins the class, the average height will be x−1 centimeters. How tall, in centimeters, is Jenelle?

A. x
B. x − 1
C. x − 6
D. x − 7
E. x − 8


The sum of the height of 6 girls is 6x. When Jenelle joins we have:

(6x + J)/7 = x - 1

6x + J = 7x - 7

J = x - 7

Answer: D
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In a classroom with 6 girls, the average height is x centimeters....  [#permalink]

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New post 26 Jul 2018, 08:30
In a classroom with 6 girls, the average height is x centimeters

=> Sum of the heights of 6 girls = 6x

Let j be the height of Janelle

After Jenelle joins the class, the average height will be x−1

Sum of height of 6 girls + height of Janelle = Total number of girls * average height

=> 6x + j = 7 * (x - 1)

=> 6x + j = 7x - 7

=> j = x - 7

Hence option D
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Re: In a classroom with 6 girls, the average height is x centimeters. If  [#permalink]

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New post 26 Jul 2018, 10:09
Bunuel wrote:
In a classroom with 6 girls, the average height is x centimeters. If Jenelle joins the class, the average height will be x−1 centimeters. How tall, in centimeters, is Jenelle?

A. x
B. x − 1
C. x − 6
D. x − 7
E. x − 8


(Total Age of 6 Girls + Jenelle) - Total Age of 6 Girls = Age of Jenelle

So, 7(x -1) - 6x = Age of Jenelle

Thus, 7x - 7 - 6x = Age of Jenelle

Or, x - 7 = Age of Jenelle , Answer must be (D)
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Re: In a classroom with 6 girls, the average height is x centimeters. If &nbs [#permalink] 26 Jul 2018, 10:09
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