aeros232 wrote:
In a country the total population is 50 million and they are distributed among 6 territories in descending order as follows, J,K,L,M,N,P where some territories can have the same amount of people. If M has 21% of the total population and P has 2 million people, what is the maximum amount of people (in millions) in territory N?
a) 4
b) 6
c) 8.5
d) 9
e) 10.5
Since there are 50 million people and M has 21% of them, M has:
0.21 x 50 million = 10.5 million people
Since the number of people in N is between the number of people in M and P, N has between 2 million and 10.5 million people. Since we want to maximize the number of people in N, we want to minimize the number of people in J, K, and L such that each has at least the number of people in M, or 10.5 million. Thus, we can say that J, K, and L have 10.5 million people each; if we add to that the 10.5 million and 2 million people in M and P, respectively, we have 10.5 x 4 + 2 = 44 million people in J, K, L, M, and P combined. Thus, the maximum number of people in N is:
50 - 44 = 6 million
Answer: B
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