In a shooting contest, each participant only shoots one times. There a

Solution.

• Probability of A hitting the target = \(0.7\).

o Probability of A not hitting the target = \(1 – 0 7 = 0.3\).
• Probability of B hitting the target = \(0.6\)

o Probability of B not hitting the target = \(1 – 0.6 = 0.4\).
• Probability of C hitting the target =\( 0.5\)

o Probability of C not hitting the target = \(1-0.5=0.5\)
• There are four cases:

o Case I: None of them hitting the target.
o Case 2: Exactly one of them hitting the target.
o Case 3: Exactly two of them hitting the target.
o Case 4: All of them hit the target.
• Case 2, 3, and 4 are favourable case.

o Probability of none of them hitting the target= P(A not hitting)*P(B not hitting)*P(C not hitting)=\(0.3*0.4*0.5=0.06\)
• P(at least one of them hitting the target)=\(1- P(none\ of\ them\ hitting\ the\ target)=1-0.06=0.94\)