nehamodak wrote:

Bunuel wrote:

In the 30-day month of June, a motorcycle dealership sold a different number of motorcycles each day. If it recorded at least one sale each day, did the dealership sell at least 525 motorcycles during June?

Notice that we are told that the dealership sold a different number of motorcycles each day.

(1) The smallest number of motorcycles sold on any one day was 3. The least number of motorcycles sold in June would be 3 + 5 + 6 + ... + 32 = (3 + 32)/2 *30 = 525. Sufficient.

(2) The second highest number of motorcycles sold on any one day was 59. The least number of motorcycles sold in June would be (1 + 2 + 3 + ... + 28) + 59 + 60 = (1 + 28)/2*28 + 119 = 525. Sufficient.

Answer: D.

I am not very clear as to how did you solve this?

how did you take up (3 + 32)/2 * 30 and also how did you choose 3 + 5+6...

For 2nd point how did you split into 28 parts and did you randamply choose 60 as highest number because I chose 61 thinking that 59 + 61 = 120 would be a whole number which will help to divide the rest number motorcylces easily

Kindly explain.

Thanks in advance

Hi NehaModak,

I am happy to help you with this .

STMT1:

We are initially told that "The smallest number of motorcycles sold on any one day was 3" .

We are also told that "motorcycle dealership sold a different number of motorcycles each day".

In a 30 day month of June we are still left with 29 days . (one day with least no [3] motor cycles sold).

therefore it will be 3+4+5+6+7+ ...................32 .

To find if the motor cycle dealer sold atleast 525 motorcycles , we need to find the sum of all motorcycles sold during the given period.

Sum = average * no of terms .

In a consecutive set , mean(average) = median . Therefore average = 17.5.

no of terms between 3 to 32 inclusive is 30 .

Sum = 17.5 * 30 = 525 (Sufficient) .

STMT2:

The second highest number of motorcycles sold on any one day was 59.

From the above stmt we can infer that both last 2 values of the june month are fixed .

As we are asked about the least number of motor cycles sold , we need to assume that the least number of motorcycles sold on 1st day will be 1 and 2nd day will be 2 and so on till day 28 . [Note : 29th and 30th day are fixed]

Therefore, the least number of motorcycles sold in June would be

(1+2+ ........28) + (29+30)

Therefore sum of motor cycles sold from 1 to 28 days will be .

14.5 (average) * 28(no of days) + [59+60]

525. (Sufficient).

Hope this helps .