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In the below diagram, points A and B lie on the circle with center O,

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In the below diagram, points A and B lie on the circle with center O, [#permalink]

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Knewton Brutal Challenge



In the below diagram, points A and B lie on the circle with center O, and rectangle ABCD and triangle ODC have the same area. If the area of the circle with center O is pi times the area of rectangle ABCD, what is the ratio of the length of the radius of the circle to the length of segment DC?
Image

(A) 2 : 1
(B) \(2 : \sqrt{2}\)
(C) 1 : 1
(D) \(1 : \sqrt{2}\)
(E) 1 : 2

Kudos for a correct solution.

[Reveal] Spoiler:
Attachment:
Brutal.GIF
Brutal.GIF [ 3.16 KiB | Viewed 1557 times ]
[Reveal] Spoiler: OA

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Re: In the below diagram, points A and B lie on the circle with center O, [#permalink]

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New post 31 Aug 2015, 17:00
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Bunuel wrote:

Knewton Brutal Challenge



In the below diagram, points A and B lie on the circle with center O, and rectangle ABCD and triangle ODC have the same area. If the area of the circle with center O is pi times the area of rectangle ABCD, what is the ratio of the length of the radius of the circle to the length of segment DC?
Image

(A) 2 : 1
(B) \(2 : \sqrt{2}\)
(C) 1 : 1
(D) \(1 : \sqrt{2}\)
(E) 1 : 2

Kudos for a correct solution.

[Reveal] Spoiler:
Attachment:
Brutal.GIF


Let OF be the altitude on DC cutting AB at E.
Here AE=EB and DF=FC (perpendicular drawn from the centre to the chord bisects the chord.)
Let R b the radius. OA=OB=R

It is given that area of triangle ODC = area of rectangle ABCD
So,
1/2 ( OF x DC ) = BC x DC

or OF = 2 BC
or OE = BC

In triangle OEB,
OE^2 + EB^2 = OB^2
or BC^2 + (1/2 DC)^2 = R^2
or BC^2 + 1/4 DC^2 = R^2 ...(1)

It is also given that Area of circle is equal to pi times area of ABCD
So,
pi x R x R = pi x BC x DC

or R^2 = BC x DC ...(2)

From (1) & (2)

BC x DC = BC^2 +1/4 DC^2
or 4 x BC x DC = 4 x BC^2 + DC^2
or DC^2 - 4 x BC x DC + 4 x BC^2 = 0
or (DC - 2BC)^2=0
or DC = 2BC
or BC = DC/2

putting this value in (2)

R^2 = (DC^2) / 2
or (R^2) / (DC^2) =1/2
or R/DC = 1/ \(\sqrt{2}\)

Answer:- D

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Re: In the below diagram, points A and B lie on the circle with center O, [#permalink]

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In the below diagram, points A and B lie on the circle with center O, [#permalink]

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New post 04 Aug 2017, 22:54
Bunuel wrote:

Knewton Brutal Challenge



In the below diagram, points A and B lie on the circle with center O, and rectangle ABCD and triangle ODC have the same area. If the area of the circle with center O is pi times the area of rectangle ABCD, what is the ratio of the length of the radius of the circle to the length of segment DC?
Image

(A) 2 : 1
(B) \(2 : \sqrt{2}\)
(C) 1 : 1
(D) \(1 : \sqrt{2}\)
(E) 1 : 2

Kudos for a correct solution.

[Reveal] Spoiler:
Attachment:
Brutal.GIF


Let the length of recangle be l and breadth be b
Area of rectangle = lb

Join the points OA . Let radius of circle be r . So, OA = r
Lets draw a line perpendicular from O to DC cutting AB at M and DC at N
So OM = \(\sqrt{r^2-(l^2)/4}\)
MN = b
ON = b+\(\sqrt{r^2-(l^2)/4}\)

Area ODC = 1/2 * (b+\(\sqrt{r^2-(l^2)/4}\))* l = Area ABCD = lb
b = \(\sqrt{r^2-(l^2)/4}\)
\(b^2 = r^2 - l^2/4\)

Area of circle = pi * area of rectangle
pi * r^2 = pi * lb
r^2 = lb = l* \(\sqrt{r^2-(l^2)/4}\)
\(r^4 = l^2 * (r^2 - l^2/4)\)
\(r^4 = r^2*l^2 -l^4/4\)
\((2r^2 - l^2)^2 = 0\)
\(r^2/l^2 = 1/2\)
r/l = 1/\(\sqrt{2}\)

Answer D
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In the below diagram, points A and B lie on the circle with center O,   [#permalink] 04 Aug 2017, 22:54
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In the below diagram, points A and B lie on the circle with center O,

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