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In the circle above, central angle AOB measures 120 degrees. If the ra

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In the circle above, central angle AOB measures 120 degrees. If the ra  [#permalink]

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17 Jan 2019, 04:25
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In the circle above, central angle AOB measures 120 degrees. If the radius of the circle is 3, what is the area of sector AOB?

A 3π/2
B 3π
C 6π
D 9π
E 18π

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Joined: 04 Jan 2015
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Re: In the circle above, central angle AOB measures 120 degrees. If the ra  [#permalink]

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17 Jan 2019, 06:58

Solution

Given:
• Angle AOB = 120 degrees
• Radius of the circle = 3

To find:
• The area of sector AOB

Approach and Working:
• Area of sector AOB = $$\frac{120}{360} * ᴨ * 3^2 = 3ᴨ$$

Hence, the correct answer is Option B

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Re: In the circle above, central angle AOB measures 120 degrees. If the ra  [#permalink]

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17 Jan 2019, 08:39
Bunuel wrote:

In the circle above, central angle AOB measures 120 degrees. If the radius of the circle is 3, what is the area of sector AOB?

A 3π/2
B 3π
C 6π
D 9π
E 18π

120/360 * 2 * pi * 3 * 3

solve
we get area = 3 pi
IMO B
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Re: In the circle above, central angle AOB measures 120 degrees. If the ra  [#permalink]

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21 Jan 2019, 19:05
Bunuel wrote:

In the circle above, central angle AOB measures 120 degrees. If the radius of the circle is 3, what is the area of sector AOB?

A 3π/2
B 3π
C 6π
D 9π
E 18π

Since the radius of the circle is 3, the area of the circle is π x 3^2 = 9π.

Since the central angle, corresponding to the sector AOB, is 120/360 = 1/3 of the circle, the area of the sector is 1/3 x 9π = 3π.

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Re: In the circle above, central angle AOB measures 120 degrees. If the ra   [#permalink] 21 Jan 2019, 19:05
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