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In the circle above, central angle AOB measures 120 degrees. If the ra

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Bunuel
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In the circle above, central angle AOB measures 120 degrees. If the ra [#permalink] New post   17 Jan 2019, 04:25
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A
B
C
D
E

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91% (00:35) correct 9% (01:34) wrong based on 39 sessions
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In the circle above, central angle AOB measures 120 degrees. If the radius of the circle is 3, what is the area of sector AOB?

A 3π/2
B 3π
C 6π
D 9π
E 18π
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B
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Re: In the circle above, central angle AOB measures 120 degrees. If the ra [#permalink] New post   17 Jan 2019, 06:58
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Solution


Given:
    • Angle AOB = 120 degrees
    • Radius of the circle = 3

To find:
    • The area of sector AOB

Approach and Working:
    • Area of sector AOB = \(\frac{120}{360} * ᴨ * 3^2 = 3ᴨ\)

Hence, the correct answer is Option B

Answer: B

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Re: In the circle above, central angle AOB measures 120 degrees. If the ra [#permalink] New post   17 Jan 2019, 08:39
Bunuel wrote:

In the circle above, central angle AOB measures 120 degrees. If the radius of the circle is 3, what is the area of sector AOB?

A 3π/2
B 3π
C 6π
D 9π
E 18π



120/360 * 2 * pi * 3 * 3

solve
we get area = 3 pi
IMO B
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Re: In the circle above, central angle AOB measures 120 degrees. If the ra [#permalink] New post   21 Jan 2019, 19:05
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Bunuel wrote:

In the circle above, central angle AOB measures 120 degrees. If the radius of the circle is 3, what is the area of sector AOB?

A 3π/2
B 3π
C 6π
D 9π
E 18π


Since the radius of the circle is 3, the area of the circle is π x 3^2 = 9π.

Since the central angle, corresponding to the sector AOB, is 120/360 = 1/3 of the circle, the area of the sector is 1/3 x 9π = 3π.

Answer: B
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Re: In the circle above, central angle AOB measures 120 degrees. If the ra [#permalink]
21 Jan 2019, 19:05
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