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In the figure above, ABCD is a square with side of length 2. If E is

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In the figure above, ABCD is a square with side of length 2. If E is [#permalink]

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New post 11 Nov 2017, 06:52
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A
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C
D
E

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In the figure above, ABCD is a square with side of length 2. If E is the midpoint of line segment AB and F is the midpoint of line segment AD, then the area of quadrilateral CFAE is

(A) 1
(B) 3/2
(C) 2
(D) 7/2
(E) 4

[Reveal] Spoiler:
Attachment:
2017-11-11_1744_001.png
2017-11-11_1744_001.png [ 6.33 KiB | Viewed 212 times ]
[Reveal] Spoiler: OA

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Re: In the figure above, ABCD is a square with side of length 2. If E is [#permalink]

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New post 11 Nov 2017, 06:59
option C

from triangle BEC and triangle FDC, FD=BE=1 DC=BC=2.

Hence by deducting these areas from the area of the square we will get the required shaded area.

Area of the two triangles=2*(1/2)*2*1
=2
Area of square= 2*2 = 4

Hence area of shaded portion=4-2=2
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Re: In the figure above, ABCD is a square with side of length 2. If E is [#permalink]

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New post 11 Nov 2017, 07:46
Area of the square ABCD is 4

Area of Triangle FDC is \(\frac{1}{2}*1*2\) = 1

Area of Triangle EBC is \(\frac{1}{2}*1*2\) = 1

Remaining Area is 4 - 1 - 1 =2

Thus, answer will be (C) 2

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Kudos [?]: 1143 [0], given: 327

Re: In the figure above, ABCD is a square with side of length 2. If E is   [#permalink] 11 Nov 2017, 07:46
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In the figure above, ABCD is a square with side of length 2. If E is

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