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In the figure above the square has two sides which are tangent to the

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In the figure above the square has two sides which are tangent to the  [#permalink]

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New post 16 May 2016, 02:44
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A
B
C
D
E

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  15% (low)

Question Stats:

77% (01:08) correct 23% (00:55) wrong based on 76 sessions

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In the figure above the square has two sides which are tangent to the circle. If the area of the circle is 4a²π, what is the area of the square?

A. 2a²
B. 4a
C. 4a²
D. 16a²
E. 64a²

Attachment:
p005-7.gif
p005-7.gif [ 607 Bytes | Viewed 2967 times ]

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Re: In the figure above the square has two sides which are tangent to the  [#permalink]

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New post 16 May 2016, 03:19
The area of the circle is 4a²π

The radius = 2a
Diameter = 4a
The diameter is equal to the side of the square = 4a
Area of the square = (4a)^2 = 16a^2

Correct Option : D
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Re: In the figure above the square has two sides which are tangent to the  [#permalink]

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New post 11 Nov 2017, 09:48
Top Contributor
Bunuel wrote:
Image
In the figure above the square has two sides which are tangent to the circle. If the area of the circle is 4a²π, what is the area of the square?

A. 2a²
B. 4a
C. 4a²
D. 16a²
E. 64a²

Attachment:
p005-7.gif


The area of the circle is 4a²π
Area of circle = π(radius
= 4a²π
= π4a²
= π(2a
So, the radius = 2a
This means the diameter = 4a (diameter is TWICE the radius)

What is the area of the square?
Each side of the square has length 4a
Area of square = side²
= (4a
= 16a²
= D

Cheers,
Brent
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Re: In the figure above the square has two sides which are tangent to the &nbs [#permalink] 11 Nov 2017, 09:48
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In the figure above the square has two sides which are tangent to the

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