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Re: In the figure above, the vertices of triangle ABC lie on the circumfer [#permalink]
Expert Reply
nechets wrote:


In the figure above, the vertices of triangle ABC lie on the circumference of circle O. What is the value of x?

(A) 35
(B) 45
(C) 55
(D) 65
(E) 70



Since sides OC and OB are radii, side OC = side OB, creating an isosceles triangle, and thus angle OCB = angle OBC = x.

Thus, we have:

2x + 70 = 180

2x = 110

x = 55

Answer: C
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Re: In the figure above, the vertices of triangle ABC lie on the circumfer [#permalink]
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nechets wrote:


In the figure above, the vertices of triangle ABC lie on the circumference of circle O. What is the value of x?

(A) 35
(B) 45
(C) 55
(D) 65
(E) 70


I'm puzzled. If one solve for angle AOB, it would imply a different result. Why?


Dear Moderator,
The figure of the above question is not visible , hope you will look into this. Thank you.
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Joined: 02 Sep 2009
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Re: In the figure above, the vertices of triangle ABC lie on the circumfer [#permalink]
Expert Reply
stne wrote:
nechets wrote:


In the figure above, the vertices of triangle ABC lie on the circumference of circle O. What is the value of x?

(A) 35
(B) 45
(C) 55
(D) 65
(E) 70


I'm puzzled. If one solve for angle AOB, it would imply a different result. Why?


Dear Moderator,
The figure of the above question is not visible , hope you will look into this. Thank you.


__________________
Fixed that. Thank you.
GMAT Club Bot
Re: In the figure above, the vertices of triangle ABC lie on the circumfer [#permalink]
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