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In the figure, the ratio of the area of parallelogram ABCD to the area

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In the figure, the ratio of the area of parallelogram ABCD to the area  [#permalink]

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New post Updated on: 24 Jul 2019, 05:14
00:00
A
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Difficulty:

  55% (hard)

Question Stats:

67% (02:47) correct 33% (02:19) wrong based on 33 sessions

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In the figure, the ratio of the area of parallelogram ABCD to the area of rectangle AECF is 5 : 3. What is the area of the rectangle AECF ?

(A) 18
(B) 24
(C) 25
(D) 50
(E) 54

Source: Nova GMAT
Difficulty Level: 700

Attachment:
2019-04-10_1139.png
2019-04-10_1139.png [ 14.88 KiB | Viewed 457 times ]

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Originally posted by Bunuel on 10 Apr 2019, 00:40.
Last edited by SajjadAhmad on 24 Jul 2019, 05:14, edited 2 times in total.
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Re: In the figure, the ratio of the area of parallelogram ABCD to the area  [#permalink]

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New post Updated on: 10 Apr 2019, 09:26
1
Bunuel wrote:
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In the figure, the ratio of the area of parallelogram ABCD to the area of rectangle AECF is 5 : 3. What is the area of the rectangle AECF ?

(A) 18
(B) 24
(C) 25
(D) 50
(E) 54

Attachment:
2019-04-10_1139.png


given area of llgram / area of rectangle = 5/3

given area of llgram 10* AF and area of rectangle = fc * af
ratio
10* af/fc*af = 5/3
fc= 6
so df = 4
and af = 25-16 ; 9 = 3
so area of rectangle = 6*3 = 18
IMO A

Originally posted by Archit3110 on 10 Apr 2019, 03:31.
Last edited by Archit3110 on 10 Apr 2019, 09:26, edited 1 time in total.
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Re: In the figure, the ratio of the area of parallelogram ABCD to the area  [#permalink]

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New post 10 Apr 2019, 09:11
IMO A


Area of Parallogm = AF * 10
area of rectangle = AF* FC

now
from the given condition
(AF*10)/(AF*FC) = 5/3

So 10/FC = 5/3

So FC = 6
DC = 4

now triangle ADF

AF ^2 = 25 - 16 =9

So AF = 3

SO Area of rectangle = 3 * 6 = 18

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Re: In the figure, the ratio of the area of parallelogram ABCD to the area   [#permalink] 10 Apr 2019, 09:11
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In the figure, the ratio of the area of parallelogram ABCD to the area

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