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Re: In what ratio did a grocer mix three varieties of tea that cost $6 per [#permalink]
Expert Reply
Bunuel wrote:
In what ratio did a grocer mix three varieties of tea that cost $6 per kg, $7 per kg and $8 per kg respectively, to make a profit of 10% by selling the mixture at $7.70 per kg?

(1) The grocer mixed 135 kg of the variety of tea that costs $7 per kg.
(2) The weight of the mixture was 315 kg.


Solution:
Pre Analysis:
  • SP of mixture \(=$7.70\) and profit earned \(=10\%\)
  • \(CP=\frac{100}{100+10}\times 7.7=\frac{100}{110}\times \frac{77}{10}=$7\)
  • CP of the mixture \(=$7\)
  • Let the amount of $6, $7 and $8 tea mixed be x, y and z respectively
  • Thus, we can write \(7=\frac{6x+7y+8z}{x+y+z}\)
    \(⇒7x+7y+7z=6x+7y+8z\)
    \(⇒x=z\)
  • Thus, we can infer that amount of $6 and $8 tea will be same
  • We are asked the value of \(x:y:z\) or \(x:y:x\)

Statement 1: The grocer mixed 135 kg of the variety of tea that costs $7 per kg
  • According to this statement, \(y=135\)
  • The required ratio will look like \(x:y:x=x:135:x\)
  • We still don't know the value of x
  • Thus, statement 1 alone is not sufficient and we cane eliminate options A and D

Statement 2: The weight of the mixture was 315 kg
  • Accordign to this statement, \(x+y+z=315\)
    \(⇒x+y+x=315\)
    \(⇒2x+y=315\)
  • We do not get the value of \(x:y:x\) from this
  • Thus, statement 2 alone is also not sufficient

Combining:
  • From statement 1, we get \(y=135\)
  • From statement 2, we get \(2x+y=315\)
  • Upon combining we can get the value of x and y and also the value of \(x:y:x\)

Hence the right answer is Option C
GMAT Club Bot
Re: In what ratio did a grocer mix three varieties of tea that cost $6 per [#permalink]
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