Bunuel wrote:
In what ratio must rice at $9.30 per Kg be mixed with rice at $10.80 per Kg so that the mixture be worth $10 per Kg?
A. 3:7
B. 7:8
C. 8:7
D. 6:5
E. 6:1
Solution:Notice that $10, the average cost, is slightly closer to $9.30 than it’s to $10.80. Furthermore, $9.30 is 70 cents less than $10 whereas $10.80 is 80 cents more than $10; therefore, we need eight kg of $9.30 rice to “balance” with seven kg of $10.80 rice to obtain an average of $10.
Alternate Solution:
Let’s determine x, the number of kg of rice costing $10.8 per kg, that should be mixed with 1 kg of rice costing $9.3 per kg such that the resulting mixture costs $10 per kg
. Since we are mixing x kg of the more expensive rice with 1 kg of the less expensive rice, we can write the following equation:
(1 * 9.3 + x * 10.8) / (1 + x) = 10
9.3 + (10.8)x = 10 + 10x
(0.8)x = 0.7
x = 0.7/0.8 = 7/8
This tells us that 1 kg of rice costing $9.3 per kg, when combined with 7/8 kg of rice costing $10.8 per kg, produces a mixture which costs $10 per kg. Thus, the ratio of the two kinds of rice is 1/(7/8) = 8/7, for the mixture costing $10 per kg. The answer is 8/7, or 8 : 7.
Answer: C