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Is 2x - 3y < x^2? 1) 2x - 3y = -2 2) x>2 and y>0

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Is 2x - 3y < x^2? 1) 2x - 3y = -2 2) x>2 and y>0 [#permalink]

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New post 24 Jul 2009, 13:25
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Is 2x - 3y < x^2?
1) 2x - 3y = -2
2) x>2 and y>0


Thanks a lot in advance. I got this from the GMATPrep sample exam. I would also appreciate various perspectives/responses/methods.

Kudos [?]: 28 [0], given: 6

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Kudos [?]: 277 [0], given: 52

Location: United States (NC)
Concentration: Strategy, Finance
Schools: UNC (Kenan-Flagler) - Class of 2013
GMAT 1: 720 Q49 V39
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Re: (Help) DS Problem #4: Please take a stab, anyone! [#permalink]

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New post 24 Jul 2009, 13:54
uzonwagba wrote:
Is 2x - 3y < x^2?
1) 2x - 3y = -2
2) x>2 and y>0


Thanks a lot in advance. I got this from the GMATPrep sample exam. I would also appreciate various perspectives/responses/methods.


1) the statement basically changes the question to is -2< x^2? this is obviously true/SUFF since anything squared will be positive.
2) so now x>2, y>0. we can try plugging in-
x=3, y=1 6-3 < 9 TRUE
x=5/2 y=1/3 5-1 = 4 < 25/4 true

You should see that you have to select y as a very small number to make the left side large enough but the x^2 is greater than 2*x (not true for x=2 but they have x>2) so no matter what value Y you pick the left will always be smaller than the right.

so D, both are SUFF
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If you like my answers please +1 kudos!

Kudos [?]: 277 [0], given: 52

Re: (Help) DS Problem #4: Please take a stab, anyone!   [#permalink] 24 Jul 2009, 13:54
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Is 2x - 3y < x^2? 1) 2x - 3y = -2 2) x>2 and y>0

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