Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jul 1206:30 AM PDT
-08:30 AM PDT
Join our webinar to master GMAT RC Main Point Questions! Learn effective strategies to decipher passage themes and purposes. Senior Verbal Expert- Sunita Singhvi will equip you with tools to navigate complexities and avoid common traps set by the GMAT.
Jun 3008:00 AM PDT
-11:59 PM PDT
Join us June 30th for 2 weeks of GMAT questions (just 8 per day) to help with your prep and to compete with your fellow GMAT Clubbers for a chance to win a prize fund of $30,000 for you and your team-mates!
Jul 0901:00 PM EDT
-02:00 PM EDT
More Target Test Prep students are earning 100th percentile GMAT scores. Don’t settle for less when the Target Test Prep course gives you everything you need to score high on the GMAT. Start your 5-day free trial today.
Jul 1211:00 AM IST
-01:00 PM IST
Attend this session to learn how to Deconstruct arguments, Pre-Think Author’s Assumptions, and apply Negation Test.
Jul 1311:00 AM EDT
-12:30 PM EDT
Looking for your GMAT motivation to break through the score plateau? Pragati improved her score by massive 160 points with strategic guidance and hard-work! Find out how personalized mentorship and a strong mindset can turn GMAT struggles into success.
Jul 1508:00 PM PDT
-09:00 PM PDT
Full-length FE mock with insightful analytics, weakness diagnosis, and video explanations!
Jul 1611:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
Updated on: 09 Oct 2021, 02:24
Originally posted by ranjitaarao on 09 Oct 2013, 10:15.
Last edited by Bunuel on 09 Oct 2021, 02:24, edited 2 times in total.
Last edited by Bunuel on 09 Oct 2021, 02:24, edited 2 times in total.
RENAMED THE TOPIC.
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
71% (01:38) correct
29%
(01:49)
wrong
based on 1773
sessions
History
Date
Time
Result
Not Attempted Yet
Is a < 2?
(1) In an xy plane, point (a,1) lies inside the circle whose equation is x^2 + y^2 = 3
(2) In an xy plane, point (a,4) lies on the line whose equation is 2y + 4x = 10
(1) In an xy plane, point (a,1) lies inside the circle whose equation is x^2 + y^2 = 3
(2) In an xy plane, point (a,4) lies on the line whose equation is 2y + 4x = 10
09 Oct 2013, 10:27
Kudos
Bookmarks
Is a < 2?
(1) In an xy plane, point (a,1) lies inside the circle whose equation is x^2 + y^2 = 3. This circle is centered at the origin and has the radius of \(\sqrt{3}\approx{1.7}\) (check here: math-coordinate-geometry-87652.html). No point inside that circle has x-coordinate greater than \(\sqrt{3}\approx{1.7}\), thus \(a<1.7<2\). Sufficient.
(2) In an xy plane, point (a,4) lies on the line whose equation is 2y + 4x = 10 --> 2*4+4x=10 --> x=1/2. Sufficient.
Answer: D.
(1) In an xy plane, point (a,1) lies inside the circle whose equation is x^2 + y^2 = 3. This circle is centered at the origin and has the radius of \(\sqrt{3}\approx{1.7}\) (check here: math-coordinate-geometry-87652.html). No point inside that circle has x-coordinate greater than \(\sqrt{3}\approx{1.7}\), thus \(a<1.7<2\). Sufficient.
(2) In an xy plane, point (a,4) lies on the line whose equation is 2y + 4x = 10 --> 2*4+4x=10 --> x=1/2. Sufficient.
Answer: D.
Updated on: 10 Apr 2015, 23:42
Originally posted by EMPOWERgmatRichC on 28 Mar 2015, 22:34.
Last edited by EMPOWERgmatRichC on 10 Apr 2015, 23:42, edited 1 time in total.
Last edited by EMPOWERgmatRichC on 10 Apr 2015, 23:42, edited 1 time in total.
Kudos
Bookmarks
Hi All,
As complex as this graphing-based DS question looks, the given Facts focus on two equations, so they're relatively easy to deal with/solve.
We're asked if A is less than 2. This is a YES/NO question.
Fact 1: In an XY plane, point (A,1) lies inside the circle whose equation is X^2 + Y^2 = 3
With the given equation and the given (X,Y) co-ordinate (A,1), we can plug in and solve for A....
A^2 + 1^2 = 3
A^2 = 2
Since we're dealing with a circle, there are two possible points that have a Y-co-ordinate of 1: (A, 1) and (-A, 1).
Since A^2 = 2, A = Root(2).
Root(2) is < Root(4)
Root(2) is < 2, so whether we're dealing with A = Root(2) or A = -Root(2), the answer to the question is ALWAYS YES.
Fact 1 is SUFFICIENT.
Fact 2: In an XY plane, point (A,4) lies on the line whose equation is 2Y + 4X = 10
Here, we have a simple line to work with, so we can substitute in the value of A (for X) and 4 (for Y), giving us....
2(4) + 4(A) = 10
8 + 4A = 10
4A = 2
A = 1/2
The answer to the question is YES.
Fact 2 is SUFFICIENT.
Final Answer:
GMAT assassins aren't born, they're made,
Rich
As complex as this graphing-based DS question looks, the given Facts focus on two equations, so they're relatively easy to deal with/solve.
We're asked if A is less than 2. This is a YES/NO question.
Fact 1: In an XY plane, point (A,1) lies inside the circle whose equation is X^2 + Y^2 = 3
With the given equation and the given (X,Y) co-ordinate (A,1), we can plug in and solve for A....
A^2 + 1^2 = 3
A^2 = 2
Since we're dealing with a circle, there are two possible points that have a Y-co-ordinate of 1: (A, 1) and (-A, 1).
Since A^2 = 2, A = Root(2).
Root(2) is < Root(4)
Root(2) is < 2, so whether we're dealing with A = Root(2) or A = -Root(2), the answer to the question is ALWAYS YES.
Fact 1 is SUFFICIENT.
Fact 2: In an XY plane, point (A,4) lies on the line whose equation is 2Y + 4X = 10
Here, we have a simple line to work with, so we can substitute in the value of A (for X) and 4 (for Y), giving us....
2(4) + 4(A) = 10
8 + 4A = 10
4A = 2
A = 1/2
The answer to the question is YES.
Fact 2 is SUFFICIENT.
Final Answer:
GMAT assassins aren't born, they're made,
Rich
