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Is nm^2 + nm - 12n = 0? (1) m^2 = 16 (2) m = -4
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25 Feb 2024, 21:29
25 Feb 2024, 21:29
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Re: Is nm^2 + nm - 12n = 0? (1) m^2 = 16 (2) m = -4
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25 Feb 2024, 21:32
25 Feb 2024, 21:32
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Expert Reply
Moving this topic to the data sufficiency sub forum.
Posted from my mobile device
Posted from my mobile device
Is nm^2 + nm - 12n = 0? (1) m^2 = 16 (2) m = -4
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Updated on: 29 Feb 2024, 22:17
Updated on: 29 Feb 2024, 22:17
1
Kudos
@1992SonalAsked: Is nm^2 + nm - 12n = 0?
Is n(m^2 + m - 12) = 0?
Is n(m+4)(m-3) = 0?
(1) m^2 = 16
If m = 4; n(m+4)(m-3) is NOT necessarily 0
If m=-4; n(m+4)(m-3) = 0
NOT SUFFICIENT
(2) m = -4
n(m+4)(m-3) = 0
SUFFICIENT
IMO B
Is n(m^2 + m - 12) = 0?
Is n(m+4)(m-3) = 0?
(1) m^2 = 16
If m = 4; n(m+4)(m-3) is NOT necessarily 0
If m=-4; n(m+4)(m-3) = 0
NOT SUFFICIENT
(2) m = -4
n(m+4)(m-3) = 0
SUFFICIENT
IMO B
