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[x] is the greatest integer less than or equal to x. Find the number

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[x] is the greatest integer less than or equal to x. Find the number [#permalink] New post   Updated on: 30 Jun 2019, 22:14
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[x] is the greatest integer less than or equal to x. Find the number of positive integers n such that [\(\frac{n}{7}\)] = [\(\frac{n}{9}\)]

A. 12
B. 13
C. 14
D. 15
E. 16
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D

Originally posted by CareerGeek on 30 Jun 2019, 01:47.
Last edited by CareerGeek on 30 Jun 2019, 22:14, edited 1 time in total.
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Re: [x] is the greatest integer less than or equal to x. Find the number [#permalink] New post   30 Jun 2019, 03:02
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When 1≤n≤6, [n/7]=[n/9]=0
When 9≤n≤13, [n/7]=[n/9]=1
When 18≤n≤20, [n/7]=[n/9]=2
When n=27, [n/7]=[n/9]=3

Total possible value of n= 6+5+3+1=15

Dillesh4096 wrote:
[x] is the greatest integer less than or equal to x. Find the number of positive integers n such that [\(\frac{n}{7}\)] = [\(\frac{n}{9}\)]

A. 12
B. 13
C. 14
D. 15
E. 16
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Re: [x] is the greatest integer less than or equal to x. Find the number [#permalink] New post   01 Jul 2019, 09:46
Hi, can someone explain the problem?
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Re: [x] is the greatest integer less than or equal to x. Find the number [#permalink] New post   02 Jul 2019, 18:48
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Dillesh4096 wrote:
[x] is the greatest integer less than or equal to x. Find the number of positive integers n such that [\(\frac{n}{7}\)] = [\(\frac{n}{9}\)]

A. 12
B. 13
C. 14
D. 15
E. 16


We see that when n is any integer from 1 to 6, inclusive, then [n/7] = 0 = [n/9]. Similarly, when n is any integer from 9 to 13, inclusive, then [n/7] = 1 = [n/9]; when n is any integer from 18 to 20, inclusive, then [n/7] = 2 = [n/9]; and lastly, when n = 27, [n/7] = 3 = [n/9].

Therefore, there are 6 + 5 + 3 + 1 = 15 integer values for n.

Answer: D
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gmatclubot
Re: [x] is the greatest integer less than or equal to x. Find the number [#permalink]
02 Jul 2019, 18:48
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