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24 Mar 2016, 16:58
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
56% (01:17) correct
44%
(01:05)
wrong
based on 308
sessions
History
Date
Time
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Not Attempted Yet
25 Mar 2016, 08:00
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MathRevolution
Is x>16?
1) x/4 > 4
2) 4/x < 1/4
1) x/4 > 4
2) 4/x < 1/4
Target question: Is x > 16?
Statement 1: x/4 > 4
Multiply both sides by POSITIVE 4 to get: x > 16
Perfect!!
Since we can answer the target question with certainty, statement 1 is SUFFICIENT
Statement 2: 4/x < 1/4
Multiply both sides by POSITIVE 4 to get: 16/x < 1
NOTE: we must avoid the temptation to multiply both sides by x to get: 16 < x. Doing so would be incorrect since we don't know whether x is POSITIVE or NEGATIVE.
Aside: for more on this, see our free video here: https://www.gmatprepnow.com/module/gmat ... /video/979
There are several values of x that satisfy statement the fact that 16/x < 1. Here are two:
Case a: x = 20, in which case x > 16
Case b: x = -1, in which case x < 16
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT
Answer = A
Cheers,
Brent
General Discussion
24 Mar 2016, 20:48
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MathRevolution
Is x>16?
1) x/4>4
2) 4/x<1/4
* A solution will be posted in two days.
1) x/4>4
2) 4/x<1/4
* A solution will be posted in two days.
Hi,
never X multiply when a variable is there in denominator..
lets see the statements--
1) x/4>4
x>16 straightway
SUFF
2)\(\frac{4}{x}<\frac{1}{4}\)
here too it is easy to x-multiply and feel th estatement to be suff, ut we have th evariable in denominator..
\(\frac{4}{x}<\frac{1}{4}\)..
\(\frac{4}{x}-\frac{1}{4}<0\)..
\(\frac{{(16-x)}}{{4x}}<0\)
so we have three cases --
1) x=0, undefined
2) x<0..
Numerator should be +ive as denominator is -ive..
hence 16-x>0 or x<16 ans is NO
3) x>0..
denominator is +ive so Num should be -ive..
hence 16-x<0 or x>16 ans is YES
two different answers.. Insuff
ans A
