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19 May 2010, 01:49
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
47% (01:40) correct
53%
(01:09)
wrong
based on 232
sessions
History
Date
Time
Result
Not Attempted Yet
Is x/3 an integer?
(1) 7x/3 = Positive integer
(2) 14x/3 = Positive integer
(1) 7x/3 = Positive integer
(2) 14x/3 = Positive integer
19 May 2010, 03:28
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dimitri92
Is \(\frac{x}{3}=integer\)?
Note that we are not told that x is an integer.
(1) \(\frac{7}{3}x\) = Positive integer --> x is of a type \(x=\frac{3k}{7}\), where \(k\) is an integer \(>{0}\). Hence x may be multiple of 3 (3, 6, ...) in this case \(\frac{x}{3}=integer\) OR x can be reduced fraction (3/7, 6/7, ...) in this case \(\frac{x}{3}\neq{integer}\). Not sufficient.
(2) \(\frac{14}{3}x\) = Positive integer --> x is of a type \(x=\frac{3n}{14}\), where \(n\) is an integer \(>{0}\). Hence x may be multiple of 3 (3, 6, ...) in this case \(\frac{x}{3}=integer\) OR x can be reduced fraction (3/14, 6/14=3/7, ...) in this case \(\frac{x}{3}\neq{integer}\). Not sufficient.
(1)+(2) No new info. If \(x=3\), answer is YES but if \(x=\frac{3}{7}\), answer is NO. Not sufficient.
Answer: E.
General Discussion
19 May 2010, 02:52
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D.
- For 7 is indivisible by 3, then x must be divisible by 3 => x/3 an integer
- 14 = 7*2, neither is divisible by 3, then x must be divisible by 3 => x/3 an integer
- For 7 is indivisible by 3, then x must be divisible by 3 => x/3 an integer
- 14 = 7*2, neither is divisible by 3, then x must be divisible by 3 => x/3 an integer
! Here's another good integer trap with excellent explanation from HRH Bunuel
