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Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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21 Jun 2010, 14:19
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Is x% of x% of y equal to x% less than y ? (1) x(x + 100) = 10,000 (2) y(y + 1) = 1 x2y = 10,000y – 100xy [multiplying by the common denominator 10,000] x2y + 100xy – 10,000y = 0 [everything to one side, because it’s quadratic] y(x2 + 100x – 10,000) = 0 [factoring] Therefore, the answer to the prompt question is affirmative if either x2 + 100x – 10,000 = 0 or y = 0.
(1) SUFFICIENT: This statement rearranges to give = 0.
(2) INSUFFICIENT: y cannot be 0, but no information is provided about x, making it impossible to determine whether x2 + 100x – 10,000 = 0.
The correct answer is A.

But, I believe D: A sufficient B: y=1 or y+1=1 therefore y=0 therefore B sufficient...
what am i missing? please help
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Re: DS question
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30 Sep 2010, 00:49
prashantbacchewar wrote: Is x% of x% of y equal to x% less than y ?
(1) x(x + 100) = 10,000 (2) y(y + 1) = 1 Question: is \(\frac{x}{100}*\frac{x}{100}*y=y(1\frac{x}{100})\)? > is \(x^2y=100y(100x)\)? > is \(x^2y=y(10,000100x)\) > is \(y(x^2+100x10,000)=0\)? Basically question is \(y=0\) or/and \(x^2+100x10,000=0\)? (1) \(x(x + 100)=10,000\) > \(x^2+100x10,000=0\). Directly gives the answer. Sufficient. (2) \(y(y+1)=1\). Here it's clear that \(y\neq{0}\), (substitute \(y=0\) in this equation: \(0(0+1)=0\neq{1}\)). So we know that \(y\neq{0}\), but don't know whether \(x^2+100x10,000=0\)? Not sufficient. Answer: A. Hope it's clear.
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Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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21 Jun 2010, 16:06
zisis wrote: Is x% of x% of y equal to x% less than y ?
(1) x(x + 100) = 10,000 (2) y(y + 1) = 1
OA: A
x2y = 10,000y – 100xy [multiplying by the common denominator 10,000] x2y + 100xy – 10,000y = 0 [everything to one side, because it’s quadratic] y(x2 + 100x – 10,000) = 0 [factoring] Therefore, the answer to the prompt question is affirmative if either x2 + 100x – 10,000 = 0 or y = 0.
(1) SUFFICIENT: This statement rearranges to give = 0.
(2) INSUFFICIENT: y cannot be 0, but no information is provided about x, making it impossible to determine whether x2 + 100x – 10,000 = 0.
The correct answer is A.

But, I believe D: A sufficient B: y=1 or y+1=1 therefore y=0 therefore B sufficient...
what am i missing? please help Question: is \(\frac{x}{100}*\frac{x}{100}*y=y(1\frac{x}{100})\)? > is \(x^2y=100y(100x)\)? > is \(x^2y=y(10,000100x)\) > is \(y(x^2+100x10,000)=0\)? Basically question is does \(y=0\) or/and \(x^2+100x10,000=0\)? (1) \(x(x + 100)=10,000\) > \(x^2+100x10,000=0\). Directly gives the answer. Sufficient. (2) \(y(y+1)=1\). Here it's clear that \(y\neq{0}\), (substitute \(y=0\) in this equation: \(0(0+1)=0\neq{1}\)). So we know that \(y\neq{0}\), but don't know whether \(x^2+100x10,000=0\)? Not sufficient. To elaborate more: the problem with your solution is that you solved incorrectly \(y(y+1)=1\). \(y(y+1)=1\) > \(y^2+y1=0\) > solving for \(y\): \(y=\frac{1\sqrt{5}}{2}\) or \(y=\frac{1+\sqrt{5}}{2}\), so \(y\neq{0}\). Answer: A. Bumping for review and further discussion*. Get a kudos point for an alternative solution! *New project from GMAT Club!!! Check HERE
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Re: DS question
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30 Sep 2010, 06:19
prashantbacchewar wrote: Is x% of x% of y equal to x% less than y ?
(1) x(x + 100) = 10,000 (2) y(y + 1) = 1 LHS = (x/100)*(x/100)*y RHS = (1x/100) * y LHS = RHS implies x^2/100 = (100x) OR x^2+100x=10000 (1) This is exactly what we need to know. Sufficient (2) The equality to be tested is independent of y. Insufficient Answer is (a)
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Re: MGMAT test 4: X Percent of X Percent
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07 Jul 2012, 03:22
Bunuel wrote: zisis wrote: Is x% of x% of y equal to x% less than y ?
(1) x(x + 100) = 10,000 (2) y(y + 1) = 1
OA: A
x2y = 10,000y – 100xy [multiplying by the common denominator 10,000] x2y + 100xy – 10,000y = 0 [everything to one side, because it’s quadratic] y(x2 + 100x – 10,000) = 0 [factoring] Therefore, the answer to the prompt question is affirmative if either x2 + 100x – 10,000 = 0 or y = 0.
(1) SUFFICIENT: This statement rearranges to give = 0.
(2) INSUFFICIENT: y cannot be 0, but no information is provided about x, making it impossible to determine whether x2 + 100x – 10,000 = 0.
The correct answer is A.

But, I believe D: A sufficient B: y=1 or y+1=1 therefore y=0 therefore B sufficient...
what am i missing? please help Question: is \(\frac{x}{100}*\frac{x}{100}*y=y(1\frac{x}{100})\)? > is \(x^2y=100y(100x)\)? > is \(x^2y=y(10,000100x)\) > is \(y(x^2+100x10,000)=0\)? Basically question is does \(y=0\) or/and \(x^2+100x10,000=0\)? (1) \(x(x + 100)=10,000\) > \(x^2+100x10,000=0\). Directly gives the answer. Sufficient. (2) \(y(y+1)=1\). Here it's clear that \(y\neq{0}\), (substitute \(y=0\) in this equation: \(0(0+1)=0\neq{1}\)). So we know that \(y\neq{0}\), but don't know whether \(x^2+100x10,000=0\)? Not sufficient. To elaborate more: the problem with your solution is that you solved incorrectly \(y(y+1)=1\). \(y(y+1)=1\) > \(y^2+y1=0\) > solving for \(y\): \(y=\frac{1\sqrt{5}}{2}\) or \(y=\frac{1+\sqrt{5}}{2}\), so \(y\neq{0}\). Answer: A. Hope it's clear. Can you explain this part \(\frac{x}{100}*\frac{x}{100}*y=y(1\frac{x}{100})\)? > my R.H.S of equation is coming as yx/100 kindly correct me if i am wrong
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Re: MGMAT test 4: X Percent of X Percent
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07 Jul 2012, 03:27
riteshgupta wrote: Bunuel wrote: zisis wrote: Is x% of x% of y equal to x% less than y ?
(1) x(x + 100) = 10,000 (2) y(y + 1) = 1
OA: A
x2y = 10,000y – 100xy [multiplying by the common denominator 10,000] x2y + 100xy – 10,000y = 0 [everything to one side, because it’s quadratic] y(x2 + 100x – 10,000) = 0 [factoring] Therefore, the answer to the prompt question is affirmative if either x2 + 100x – 10,000 = 0 or y = 0.
(1) SUFFICIENT: This statement rearranges to give = 0.
(2) INSUFFICIENT: y cannot be 0, but no information is provided about x, making it impossible to determine whether x2 + 100x – 10,000 = 0.
The correct answer is A.

But, I believe D: A sufficient B: y=1 or y+1=1 therefore y=0 therefore B sufficient...
what am i missing? please help Question: is \(\frac{x}{100}*\frac{x}{100}*y=y(1\frac{x}{100})\)? > is \(x^2y=100y(100x)\)? > is \(x^2y=y(10,000100x)\) > is \(y(x^2+100x10,000)=0\)? Basically question is does \(y=0\) or/and \(x^2+100x10,000=0\)? (1) \(x(x + 100)=10,000\) > \(x^2+100x10,000=0\). Directly gives the answer. Sufficient. (2) \(y(y+1)=1\). Here it's clear that \(y\neq{0}\), (substitute \(y=0\) in this equation: \(0(0+1)=0\neq{1}\)). So we know that \(y\neq{0}\), but don't know whether \(x^2+100x10,000=0\)? Not sufficient. To elaborate more: the problem with your solution is that you solved incorrectly \(y(y+1)=1\). \(y(y+1)=1\) > \(y^2+y1=0\) > solving for \(y\): \(y=\frac{1\sqrt{5}}{2}\) or \(y=\frac{1+\sqrt{5}}{2}\), so \(y\neq{0}\). Answer: A. Hope it's clear. Can you explain this part \(\frac{x}{100}*\frac{x}{100}*y=y(1\frac{x}{100})\)? > my R.H.S of equation is coming as yx/100 kindly correct me if i am wrong Consider this: 10% less than \(y\) is \(y*(1\frac{10}{100})=y*0.9\), the same way "\(x%\) less than \(y\)": is \(y(1\frac{x}{100})\). Hope it's clear.
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Is x% of x% of y equal to x% less than y ?
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25 Aug 2012, 22:26
Hello Guys, I am new to GMAT preparation so need some help from you veterans .I cannot understand this question.As per my understanding x% of x% of any number is always less than x% of that number.For example, 10% of 10% of 100 : Since there is no bracket ,I can start from the left hand side .10% of 10% is 1% . 1% of 100 is 1. Now to the second part ...x% less than y,which means 10% less than y,which is nothing but 90.So 1 is always less than 90 . Obvously I have got it all wrong ,but I cannot interpret it in any other manner .Please help . Regards, arijitb1980
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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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25 Aug 2012, 22:56
arijitb1980 wrote: Hello Guys, I am new to GMAT preparation so need some help from you veterans .I cannot understand this question.As per my understanding x% of x% of any number is always less than x% of that number.For example, 10% of 10% of 100 : Since there is no bracket ,I can start from the left hand side .10% of 10% is 1% . 1% of 100 is 1. Now to the second part ...x% less than y,which means 10% less than y,which is nothing but 90.So 1 is always less than 90 . Obvously I have got it all wrong ,but I cannot interpret it in any other manner .Please help . Regards, arijitb1980 From your computations it is clear that \(x\) cannot be 10. But it doesn't mean that there is no value of \(x\) for which the equality holds. Translating the question into an equation: is \(\frac{x}{100}*\frac{x}{100}y=(1\frac{x}{100})y\)? (1) If \(y=0,\) then the equality certainly holds. Dividing through by \(y,\) the equation becomes \(x^2+x10,000=0.\) You can solve this quadratic and the positive root is approximately \(61.8.\) So, here is the answer: for \(x=61.8\), \(x%\) of \(x%\) of \(y\) is \(x%\) less than \(y.\) Sufficient. (2) We can deduce that \(y\neq0\) but we don't know anything about \(x.\) Not sufficient. Answer A
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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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08 Dec 2012, 11:48
I do not understand the question. Why did you rephrase the question FROM "Is x% of x% of y equal to x% less than y ?" TO Is y = 0 ?
When I read the question, I wrote down (x%((x%)y)) = x%<y
Please help. thanks in advance.



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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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Re: Is x% of x% of y equal to x% less than y ?
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17 Oct 2013, 05:02
adg142000 wrote: Is x% of x% of y equal to x% less than y ?
(1) x(x + 100) = 10,000 (2) y(y + 1) = 1 what I wanted to know about the above question is that while plugging in values can we use ve values for Y. my approach for the above was i reduced the word statement to equation with statement 1 as : \(xy/(x+100)=y(1x/100)\)? ,,and took the values x=10 and y =10 for which 100/110< 9 but for x=10 and y=10 100/110 is not less than 9. I got this problem wrong for this reason. Do for percentage problems ve sign has to be ignored???
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Re: Is x% of x% of y equal to x% less than y ?
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17 Oct 2013, 05:31
adg142000 wrote: my approach for the above was i reduced the word statement to equation with statement 1 as :
\(xy/(x+100)=y(1x/100)\)? ,,and took the values x=10 and y =10 for which 100/110< 9
but for x=10 and y=10
100/110 is not less than 9.
I got this problem wrong for this reason. Do for percentage problems ve sign has to be ignored??? Pluggingin is not the correct approach for this question, as because the values of x and y are fixed by the fact statements. We have to prove whether \(\frac{x}{100}*\frac{x}{100}*y = y*(1\frac{x}{100})\) or not > \(\frac{x}{100}*y[\frac{x}{100}*+1] = y\) \(\to\)After rearranging we get \(x*(x+100)*y = 10000y \to Is y*[x*(x+100)10000]=0?\) From F.S 1, we know that x*(x+100) = 10000, thus Sufficient. From F.S 2, we know only the value of y, and nothing about x. Insufficient A. I believe negative percentage makes sense when there is a decrease . So it will not be wrong to say for example that the decrease in the value was 5% or the percentage change was 5%.
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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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07 Jul 2015, 14:19
prashantbacchewar wrote: Is x% of x% of y equal to x% less than y ?
(1) x(x + 100) = 10,000 (2) y(y + 1) = 1 Question : Is (x/100)*(x/100)*y = y  (x/100)*y Question : Is (x/100)*(x/100)*y = y[1  (x/100)] Question : Is (x/100)^2 = (100  x)/100 Question : Is (x)^2 = (100  x)*100? Question : Is x^2 +100x = 10,000? Question : Is x(x +100) = 10,000?Statement 1: x(x + 100) = 10,000 SUFFICIENT Statement 2: y(y + 1) = 1NOT SUFFICIENTAnswer: Option A
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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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07 Jul 2015, 14:24
How did rhs become y(1x/100)? Please explain i am unable to understand...



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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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07 Jul 2015, 14:33
Shreks1190 wrote: How did rhs become y(1x/100)? Please explain i am unable to understand... x% less than y means "y  (x% of y)"which is same as y  (x/100)*yTake y common the expression becomes y[1  (x/100)] I hope it helps!
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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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26 Jul 2015, 09:57
Bunuel wrote: prashantbacchewar wrote: Is x% of x% of y equal to x% less than y ?
(1) x(x + 100) = 10,000 (2) y(y + 1) = 1 Question: is \(\frac{x}{100}*\frac{x}{100}*y=y(1\frac{x}{100})\)? > is \(x^2y=100y(100x)\)? > is \(x^2y=y(10,000100x)\) > is \(y(x^2+100x10,000)=0\)? Basically question is \(y=0\) or/and \(x^2+100x10,000=0\)? (1) \(x(x + 100)=10,000\) > \(x^2+100x10,000=0\). Directly gives the answer. Sufficient. (2) \(y(y+1)=1\). Here it's clear that \(y\neq{0}\), (substitute \(y=0\) in this equation: \(0(0+1)=0\neq{1}\)). So we know that \(y\neq{0}\), but don't know whether \(x^2+100x10,000=0\)? Not sufficient. Answer: A. Hope it's clear. Hello Bunuel, I could not understand one thing that why did you not eliminate y from \(x^2y=100y(100x)\) and kept till the end ?. As far as I know percentages dont have sign.



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Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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26 Jul 2015, 10:17
anurag356 wrote: Bunuel wrote: prashantbacchewar wrote: Is x% of x% of y equal to x% less than y ?
(1) x(x + 100) = 10,000 (2) y(y + 1) = 1 Question: is \(\frac{x}{100}*\frac{x}{100}*y=y(1\frac{x}{100})\)? > is \(x^2y=100y(100x)\)? > is \(x^2y=y(10,000100x)\) > is \(y(x^2+100x10,000)=0\)? Basically question is \(y=0\) or/and \(x^2+100x10,000=0\)?(1) \(x(x + 100)=10,000\) > \(x^2+100x10,000=0\). Directly gives the answer. Sufficient. (2) \(y(y+1)=1\). Here it's clear that \(y\neq{0}\), (substitute \(y=0\) in this equation: \(0(0+1)=0\neq{1}\)). So we know that \(y\neq{0}\), but don't know whether \(x^2+100x10,000=0\)? Not sufficient. Answer: A. Hope it's clear. Hello Bunuel, I could not understand one thing that why did you not eliminate y from \(x^2y=100y(100x)\) and kept till the end ?. As far as I know percentages dont have sign. 1. We are concerned about the sign when we are dealing with inequalities, not equations. 2. Have you read the highlighted part? y = 0 also satisfies the equation hence we cannot reduce by it because division by 0 is not allowed.
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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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04 Aug 2017, 06:54
Hey Bunuel can you please help me here? I took the answer as C, because only when y is not equal to 0 is the first statement valid. As we do not yet know whether y is not equal to 0, we will need the second equation. I think we cannot take the first equation as there is no mention of y and it breaks when y=0.



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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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25 Aug 2018, 17:34
mehrotrayashraj wrote: Hey Bunuel can you please help me here? I took the answer as C, because only when y is not equal to 0 is the first statement valid. As we do not yet know whether y is not equal to 0, we will need the second equation. I think we cannot take the first equation as there is no mention of y and it breaks when y=0. When we know \(a=0\), we can conclude that \(a*b = 0\) Statement 1 says \(x^2+100x−10,000=0\), so \((x^2+100x−10,000)*y=0\) > YES. Sufficient. Statement 2 says \(y≠0\) If \(x^2+100x−10,000=0\), then \((x^2+100x−10,000)*y=0\) > YES If \(x^2+100x−10,000≠0\), then \((x^2+100x−10,000)*y≠0\) > NO > Statement 2 alone is not sufficient. Thus the answer is A.
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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) =
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26 Aug 2018, 02:38
mehrotrayashraj wrote: Hey Bunuel can you please help me here? I took the answer as C, because only when y is not equal to 0 is the first statement valid. As we do not yet know whether y is not equal to 0, we will need the second equation. I think we cannot take the first equation as there is no mention of y and it breaks when y=0. The question asks: is \(y(x^2+100x10,000)=0\)? So, is is \(y=0\) OR/AND \(x^2+100x10,000=0\)? Notice that IF \(x^2+100x10,000=0\), then no matter what the value of y is, \(y(x^2+100x10,000)=y*0=0\). (1) says that \(x^2+100x10,000=0\), thus \(y(x^2+100x10,000)=y*0=0\). Hope it helps.
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Re: Is x% of x% of y equal to x% less than y ? (1) x(x + 100) = &nbs
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26 Aug 2018, 02:38






