|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
21 Mar 2017, 05:39
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
56% (01:47) correct
44%
(01:46)
wrong
based on 77
sessions
History
Date
Time
Result
Not Attempted Yet
21 Mar 2017, 07:00
Kudos
Bookmarks
Bunuel
Please correct me if I'm missing something.
(1) x^2 + y^2 = 5 - Equation of a circle with radius root(5). Since the circle passes through all 4 quadrants, xy will be negative if we choose a point on circumference of the circle from 2nd and 4th quadrant. xy will be positive if we choose a point on circumference from 1st and 3rd quadrant. - Not sufficient.
(2) x+y > 3. Can be any line passing through quadrant 1, 2, and 4. Again xy can be negative or positive. - Not sufficient.
(1) + (2) The line and the circle doesn't meet. So not sufficient.
Hence E.
Cheers!
16 Jul 2018, 03:43
Kudos
Bookmarks
Bunuel
We can clearly see that statement 1 and 2 by themselves are insuff. After plugging some numbers I couldn't get that xy<1 hence choose C.
but can anyone explain how x+y can be greater than 3 and \(x^2 +y^2\) = 5
Please can some one give me values of X and Y which satisfy both the statements
as of now I can only come up with x= -2, or 2 and y = -1 or 1 and vice versa in both cases X+ Y \(\leq\) 3
I understand that X and Y need not be integers then lets take \(y^2\)= 5 and x= 0 ( for \(X^2\)+\(Y^2\)= 5) then y ~2.23 here also x+y < 3
so it is possible that \(x^2\) + \(y^2\)= 5 and x + y > 3
Thank you.
