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# John and Peter are among the nine players a basketball coach

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Director
Joined: 23 May 2008
Posts: 757
John and Peter are among the nine players a basketball coach [#permalink]

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30 Aug 2008, 16:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

John and Peter are among the nine players a basketball coach can choose from to field a five-player team. If all five players are chosen at random, what is the probability of choosing a team that includes John and Peter?

1/9
1/6
2/9
5/18
1/3
Director
Joined: 23 Sep 2007
Posts: 767

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30 Aug 2008, 16:30
bigtreezl wrote:
John and Peter are among the nine players a basketball coach can choose from to field a five-player team. If all five players are chosen at random, what is the probability of choosing a team that includes John and Peter?

1/9
1/6
2/9
5/18
1/3

D

without restrictions, the number of possible combos is C(9,5) = 126

if J and P are on the same team, that leaves the coach to pick 3 out of 7 player, so C(7,3) = 35

35/126 = 5/18
SVP
Joined: 07 Nov 2007
Posts: 1761
Location: New York

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31 Aug 2008, 22:27
bigtreezl wrote:
John and Peter are among the nine players a basketball coach can choose from to field a five-player team. If all five players are chosen at random, what is the probability of choosing a team that includes John and Peter?

1/9
1/6
2/9
5/18
1/3

p= (2C2*7C3) / 9C5 = 5/18
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Re: mgmat probability   [#permalink] 31 Aug 2008, 22:27
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# John and Peter are among the nine players a basketball coach

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