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Re: John deposited $10,000 to open a new savings account that [#permalink]
hyder27
I have quite similar strategies as Mr Bunuel does, but with a little more detailed explanation.

Step 1:
4% interest on $10,000 per year (12 months). However, his account will receive profit after 3 months as it is on a compound interest basis. So let's find out the amount of interest after the first 3 months first:

(10000 x 4 x 3)
________________ = 100
(100 x12)

So, after 3 months his capital is 10000 (the original amount) + 100 (the profit) = 10100

Step 2:
In the second 3 months, he will earn a profit on the capital amount and also on the profit earned in the first three months.

So, the profit for the second 3 months is:
(10100 x 4 x 3)
________________ = 101
(100 x12)

In total, he receives a profit of 100+101 = 201
His capital was 10000
Therefore after 6 months, he receives 10000 + 201 = 10201
Answer D
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Re: John deposited $10,000 to open a new savings account that [#permalink]
To calculate the amount of money in John's account after 6 months, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:
A is the final amount
P is the principal amount (initial deposit)
r is the annual interest rate (as a decimal)
n is the number of times the interest is compounded per year
t is the time in years

In this case, John's initial deposit is $10,000, the annual interest rate is 4% (0.04 as a decimal), the interest is compounded quarterly (n = 4), and the time is 6 months (0.5 years).

Plugging these values into the formula:

A = 10,000(1 + 0.04/4)^(4*0.5) = 10,000(1 + 0.01)^2 = 10,000(1.01)^2 = 10,201

Therefore, the amount of money in John's account 6 months after it was opened is approximately $10,201.

The closest option to this value is (D) $10,201.
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Re: John deposited $10,000 to open a new savings account that [#permalink]
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