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Joined: 22 Jan 2012
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Ken left a job paying $75,000 per year to accept a sales job
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23 Mar 2012, 22:42
Question Stats:
73% (02:25) correct 27% (02:18) wrong based on 284 sessions
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Ken left a job paying $75,000 per year to accept a sales job paying $45,000 per year plus 15 percent commission. If each of his sales is for $750, what is the least number of sales he must make per year if he is not to lose money because of the change? A. 40 B. 200 C. 266 D. 267 E. 600 I can easily compute that 0.15(750) = $112.50 of commission per sale; which means that
[30,000/112.5] sales would be required in order to not lose money when compared to his previous job...
It sounds weird, but I'm having trouble dividing fractions or estimating the correct answer...
I manipulated the fraction to [60,000/225] = [2400/9] = [24/9]*100
are there any tips or topics on learning to divide fractions properly... for example i don't think i'd be able to determine that the answer was D over C...
thanks in advance
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Re: Ken left a job paying $75,000 per year to accept a sales job
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24 Mar 2012, 02:17
Ken left a job paying $75,000 per year to accept a sales job paying $45,000 per year plus 15 percent commission. If each of his sales is for $750, what is the least number of sales he must make per year if he is not to lose money because of the change? A. 40 B. 200 C. 266 D. 267 E. 600 In order not to lose money because of the change Ken's total commission must be at least $75,000$45,000=$30,000, so total sales must be at least $30,000/0.15=$200,000. Which means that he must make at least $200,000/750=800/3=266.6 sales, so 267 sales. Answer: D. Hope it helps.
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Re: Ken left a job paying $75,000 per year to accept a sales job
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23 Mar 2012, 23:31
essarr wrote: hi, i know this question has been posted before; but my question is to ask how people go about either estimating the division or actually getting the correct answer
ken left a job paying $75,000 per year to accept a sales job paying $45,000 per year plus 15 percent commission. If each of his sales is for $750, what is the least number of sales he must make per year if he is not to lose money because of the change?
a. 40 b. 200 c. 266 d. 267 e. 600
I can easily compute that 0.15(750) = $112.50 of commission per sale; which means that
[30,000/112.5] sales would be required in order to not lose money when compared to his previous job...
It sounds weird, but I'm having trouble dividing fractions or estimating the correct answer...
I manipulated the fraction to [60,000/225] = [2400/9] = [24/9]*100
are there any tips or topics on learning to divide fractions properly... for example i don't think i'd be able to determine that the answer was D over C...
thanks in advance after simplifying it i got 800/3 = 266.66 In round figure which is 267.
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Re: Ken left a job paying $75,000 per year to accept a sales job
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25 Mar 2012, 10:59
Ans : D
75000 = 45000 + [15/100 [750] * x]
30000 = [15 * 15 / 10] * x [30000 * 10] / [15 * 15] = x 266.6 = x 267 = x



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Re: Ken left a job paying $75,000 per year to accept a sales job
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15 Aug 2013, 03:30
Bumping for review and further discussion.
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Re: Ken left a job paying $75,000 per year to accept a sales job
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15 Aug 2013, 05:48
essarr wrote: hi, i know this question has been posted before; but my question is to ask how people go about either estimating the division or actually getting the correct answer
Ken left a job paying $75,000 per year to accept a sales job paying $45,000 per year plus 15 percent commission. If each of his sales is for $750, what is the least number of sales he must make per year if he is not to lose money because of the change?
A. 40 B. 200 C. 266 D. 267 E. 600
I can easily compute that 0.15(750) = $112.50 of commission per sale; which means that
[30,000/112.5] sales would be required in order to not lose money when compared to his previous job...
It sounds weird, but I'm having trouble dividing fractions or estimating the correct answer...
I manipulated the fraction to [60,000/225] = [2400/9] = [24/9]*100
are there any tips or topics on learning to divide fractions properly... for example i don't think i'd be able to determine that the answer was D over C...
thanks in advance 30000 = 15% × 750 × n or, n = 800/3 = 266.666 So 267 sales.(Answer) 266 sales would decrease his earnings.
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Re: Ken left a job paying $75,000 per year to accept a sales job
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29 Jun 2017, 19:58
Let's be smart about these problem types. In fact, once I share this, you will pray you get a problem like this on test day.
The question asks us for the LEAST number of sales Ken must make to break even. Knowing that the makers of the GMAT will try to trap us with the wrong answer, we can quickly narrow the correct answer to one of two choices: C or D. We can assume without even doing any math that the answer will be some fractional answer. The trap here is that we round down instead of rounding up like the question asks us to do by asking for the LEAST number of sales he must make.
Without even putting pen to paper, I can be 99% confident that the answer is D, which is the larger of the two answers since the question asks for the LEAST number of sales he must make.
Now  if I am short for time on test day, then this can be a fabulous way of making up time. If I have time to work out the answer that I can have 100% confidence in, then I will do the algebra, as others have stated.
Happy GMAT Hunting...



Intern
Joined: 29 Mar 2018
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Re: Ken left a job paying $75,000 per year to accept a sales job
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27 Jul 2018, 09:40
Hi, We can solve it easily by making a simple eqn.. Consider the no. Of sales as x. So, 45,000+(15/100)*750*X=75,000 This gives, X=266.6 X=267 Option D Sent from my Lenovo A6020a40 using GMAT Club Forum mobile app



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Joined: 20 Apr 2019
Posts: 81

Re: Ken left a job paying $75,000 per year to accept a sales job
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11 Aug 2019, 01:35
How do we know that the commission is received on total sales $ and not on each 750$ sale?




Re: Ken left a job paying $75,000 per year to accept a sales job
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11 Aug 2019, 01:35






