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In a set of numbers from 100 to 1000 inclusive, how many integers are

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alimad
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In a set of numbers from 100 to 1000 inclusive, how many integers are [#permalink] New post   Updated on: 19 May 2015, 05:28
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In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit "5"?

A. 180
B. 196
C. 286
D. 288
E. 324

M03-12

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D

Originally posted by alimad on 13 May 2008, 18:56.
Last edited by Bunuel on 19 May 2015, 05:28, edited 1 time in total.
Renamed the topic, edited the question, added the OA and moved to PS forum.
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are [#permalink] New post   19 May 2015, 05:29
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alimad wrote:
In a set of numbers from 100 to 1000 inclusive, how many integers are odd and do not contain the digit "5"?

A. 180
B. 196
C. 286
D. 288
E. 324

M03-12


Examine what digits these set members can contain:

First digit (hundreds): 8 choices (1, 2, 3, 4, 6, 7, 8, 9 - cannot be 0 or 5)
Second digit (tens): 9 choices (0, 1, 2, 3, 4, 6, 7, 8, 9 - cannot be 5)
Last digit (units): 4 choices (1, 3, 7, 9 - cannot be 0, 2, 4, 5, 6, 8)

The answer is 8∗9∗4=32∗9=288.

Answer: D.
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vshaunak@gmail.com
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are [#permalink] New post   13 May 2008, 20:11
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Should be 288.
We have to find the total number of 3-digit odd numbers not having 5 as a digit.
Units digits will be among 1,3,7,9
Tenth digits will be among 0,1,2,3,4,6,7,8,9
Hundredth digits will be among 1,2,3,4,6,7,8,9
So total numbers = 4*9*8 =288
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are [#permalink] New post   24 Jan 2009, 14:36
Can someone tell my why we multiply 4*8*9, whats the logic behind multiplying versus another approach?

Thanks,
Ali
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are [#permalink] New post   24 Jan 2009, 16:07
x-ALI-x wrote:
Can someone tell my why we multiply 4*8*9, whats the logic behind multiplying versus another approach?

Thanks,
Ali


we need to find odd numbers without digit 5 from 100 to 1000 (i.e same as odd numbers without digit 5 from 100 to 999)

let say number= XYZ
Z= units digit
Y= tenths digit
X= Hundredth's digit

For any 3 digit number to be odd, Unit digit must be odd
So Z can be filled with 1,3,7,9 (we are exlcuding digit 5) = 4 ways.
Y can be filled with 0,1,2,3,4,6,7,8,9 (we are ecluding digit 5) = 9 ways
X can be filled with 1,2,3,4,6,7,8,9 (we are exlcuding digits 0 and 5 .. ) = 8 ways

No of ways= 4*9*8= 288
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are [#permalink] New post   02 Jan 2024, 04:05
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Re: In a set of numbers from 100 to 1000 inclusive, how many integers are [#permalink]
02 Jan 2024, 04:05
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