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M07-25

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M07-25 [#permalink]

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New post 16 Sep 2014, 00:35
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84% (01:34) correct 16% (00:47) wrong based on 32 sessions

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In March, 25 percent of a certain company's 80 customers were females, and in April, 40 percent of its 160 customers were males. What is the percent increase from March to April in the number of female customers of the company?

A. 38%
B. 68.75%
C. 79.17%
D. 220%
E. 380%
[Reveal] Spoiler: OA

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Re M07-25 [#permalink]

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New post 16 Sep 2014, 00:35
Official Solution:

In March, 25 percent of a certain company's 80 customers were females, and in April, 40 percent of its 160 customers were males. What is the percent increase from March to April in the number of female customers of the company?

A. 38%
B. 68.75%
C. 79.17%
D. 220%
E. 380%


In March, the company had \(0.25*80=20\) female customers: \(0.25*80=20\);

In April, the company had \((1-0.4)*160=96\) female customers;

General formula for percent increase or decrease, (percent change): \(\text{percent}=\frac{\text{Change}}{\text{Original}}*100\), so \(\text{percent}=\frac{96-20}{20}*100=380%\)


Answer: E
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: M07-25 [#permalink]

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New post 17 Mar 2018, 05:26
Female customers in the month of March, 0.25*80 = 20.

Female customers in the month of April, 60% of 160 customers = 0.6*160 = 96.

% increase = (increase/original)*100 = (96-20/20)*100 = (76/20)*100 = 380%.

The answer is (E).
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Re: M07-25   [#permalink] 17 Mar 2018, 05:26
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