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M07-25

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M07-25  [#permalink]

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New post 16 Sep 2014, 00:35
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

77% (01:50) correct 23% (01:14) wrong based on 30 sessions

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Math Expert
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Re M07-25  [#permalink]

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New post 16 Sep 2014, 00:35
Official Solution:

In March, 25 percent of a certain company's 80 customers were females, and in April, 40 percent of its 160 customers were males. What is the percent increase from March to April in the number of female customers of the company?

A. 38%
B. 68.75%
C. 79.17%
D. 220%
E. 380%


In March, the company had \(0.25*80=20\) female customers: \(0.25*80=20\);

In April, the company had \((1-0.4)*160=96\) female customers;

General formula for percent increase or decrease, (percent change): \(\text{percent}=\frac{\text{Change}}{\text{Original}}*100\), so \(\text{percent}=\frac{96-20}{20}*100=380%\)


Answer: E
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Re: M07-25  [#permalink]

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New post 17 Mar 2018, 05:26
Female customers in the month of March, 0.25*80 = 20.

Female customers in the month of April, 60% of 160 customers = 0.6*160 = 96.

% increase = (increase/original)*100 = (96-20/20)*100 = (76/20)*100 = 380%.

The answer is (E).
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Re: M07-25  [#permalink]

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New post 14 Sep 2019, 23:55
Bunuel wrote:
Official Solution:

In March, 25 percent of a certain company's 80 customers were females, and in April, 40 percent of its 160 customers were males. What is the percent increase from March to April in the number of female customers of the company?

A. 38%
B. 68.75%
C. 79.17%
D. 220%
E. 380%


In March, the company had \(0.25*80=20\) female customers: \(0.25*80=20\);

In April, the company had \((1-0.4)*160=96\) female customers;

General formula for percent increase or decrease, (percent change): \(\text{percent}=\frac{\text{Change}}{\text{Original}}*100\), so \(\text{percent}=\frac{96-20}{20}*100=380%\)


Answer: E


Hey Brunel,

I have a silly question - if the total number of customers increase - while figuring percent increase, why aren't we making the base same?
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Re: M07-25   [#permalink] 14 Sep 2019, 23:55
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