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Re: M08-30 [#permalink]
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We can solve this question in the following way :

We have total 5 children out of which 2 are siblings and 3 are not, so if we first arrange 3 children, then we get = 3!

If these 3 children are seated, then we have 4 places remaining for those 2 siblings in which they cannot seat together

_ child 1 _ child 2 _ child 3 _ = so we have 4 places remaining, so 4P2

No. of ways in which 2 siblings do not sit together = 3! AND 4P2 ----> (AND = Multiplication, OR = Addition)
= (3*2*1) * (4*3)
= 6 * 12
= 72 ways

Hence, option C is correct
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Re: M08-30 [#permalink]
*If these 3 children are seated, then we have 4 places remaining for those 2 siblings in which they cannot seat together*

Please, could you explain why we have 4 places remaining while 3 out of 5 are occupied ?
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Re: M08-30 [#permalink]
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Samé wrote:
*If these 3 children are seated, then we have 4 places remaining for those 2 siblings in which they cannot seat together*

Please, could you explain why we have 4 places remaining while 3 out of 5 are occupied ?


The siblings can occupy positions either between the children labeled 1, 2, and 3, or at either end of this group of children:

__ (child 1) __ (child 2) __ (child 3) __
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Re: M08-30 [#permalink]
Hi Bunuel!
Is it possible to share the solution as per Fundamental Counting principle method?Bunuel
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Re: M08-30 [#permalink]
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ADARSHREDDY1 wrote:
Hi Bunuel!
Is it possible to share the solution as per Fundamental Counting principle method?Bunuel

­The Fundamental Counting Principle states that if an event has x possible outcomes and a different independent event has y possible outcomes, then there are xy possible ways the two events could occur together. We do not have two different independent events in this question, so not sure how you would apply this here.
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M08-30 [#permalink]
Bunuel

It may sound stupid, but iam going to ask it anyway. When you say 2 sibilings, out how many people do 2 sibilings exist?

I thought 2 sibilings consist of 4 people: Sibiling-1=(brother,sister), and Sibiling 2 (brother,sister). That is why i did the following: 5!= 120 and then, 2 sibilings=4 people compress it in two plus the last one in the group, i got 3!= 6 and 6* 2!= 12.

But then, when i subtracted the 12 from the 120 (120-12)= 108 was not among the answer choices.

My approach is good, but it seems the way i counted/interpreted 2 sibilings was wrong.


Thanks in advance!­
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Re: M08-30 [#permalink]
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Rebaz wrote:
Bunuel

It may sound stupid, but iam going to ask it anyway. When you say 2 sibilings, out how many people do 2 sibilings exist?

I thought 2 sibilings consist of 4 people: Sibiling-1=(brother,sister), and Sibiling 2 (brother,sister). That is why i did the following: 5!= 120 and then, 2 sibilings=4 people compress it in two plus the last one in the group, i got 3!= 6 and 6* 2!= 12.

But then, when i subtracted the 12 from the 120 (120-12)= 108 was not among the answer choices.

My approach is good, but it seems the way i counted/interpreted 2 sibilings was wrong.


Thanks in advance!­

­The term "two siblings" refers to two people. Each sibling is one individual, so when you say "two siblings," you are talking about two individuals who are brothers, sisters, or one of each.
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