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# M22-04

Author Message
Director
Status: Gonna rock this time!!!
Joined: 22 Jul 2012
Posts: 506

Kudos [?]: 72 [0], given: 562

Location: India
GMAT 1: 640 Q43 V34
GMAT 2: 630 Q47 V29
WE: Information Technology (Computer Software)

### Show Tags

24 Feb 2013, 04:54
6 male and 8 female employees work in the IT department. If an expert group has to be formed including 2 men and 1 woman, how many variants are possible?
60
80
120
150
180

Please help explain the concept.. I am having a hard time understanding formulas of permutations and combinations.
_________________

hope is a good thing, maybe the best of things. And no good thing ever dies.

Who says you need a 700 ?Check this out : http://gmatclub.com/forum/who-says-you-need-a-149706.html#p1201595

My GMAT Journey : http://gmatclub.com/forum/end-of-my-gmat-journey-149328.html#p1197992

Kudos [?]: 72 [0], given: 562

VP
Joined: 23 Mar 2011
Posts: 1112

Kudos [?]: 508 [1], given: 466

Concentration: Healthcare, Strategy
Schools: Duke '16 (M)

### Show Tags

24 Feb 2013, 05:04
1
KUDOS
Sachin9 wrote:
6 male and 8 female employees work in the IT department. If an expert group has to be formed including 2 men and 1 woman, how many variants are possible?
60
80
120
150
180

Please help explain the concept.. I am having a hard time understanding formulas of permutations and combinations.

3 step process:

1.) you need to SELECT 2 males out of 6. use 6C2 = 15
2.) then 1 female out of 8. 8C1=8
3.) number of ways to select 2 males AND 1 female = 15x8 (use multiplication when you see 'and' & use addition when you see 'or')

where is/was the gap in understanding? (the third step?)

Kudos [?]: 508 [1], given: 466

Director
Status: Gonna rock this time!!!
Joined: 22 Jul 2012
Posts: 506

Kudos [?]: 72 [0], given: 562

Location: India
GMAT 1: 640 Q43 V34
GMAT 2: 630 Q47 V29
WE: Information Technology (Computer Software)

### Show Tags

24 Feb 2013, 05:09
jumsumtak wrote:
Sachin9 wrote:
6 male and 8 female employees work in the IT department. If an expert group has to be formed including 2 men and 1 woman, how many variants are possible?
60
80
120
150
180

Please help explain the concept.. I am having a hard time understanding formulas of permutations and combinations.

3 step process:

1.) you need to SELECT 2 males out of 6. use 6C2 = 15
2.) then 1 female out of 8. 8C1=8
3.) number of ways to select 2 males AND 1 female = 15x8 (use multiplication when you see 'and' & use addition when you see 'or')

where is/was the gap in understanding? (the third step?)

ok this seems easy.. 6C2 = (6 * 5 )/(2*1) .. but the explanation given in GC CAT expands 6C2 in a different way . All good now. Thanks mate!
_________________

hope is a good thing, maybe the best of things. And no good thing ever dies.

Who says you need a 700 ?Check this out : http://gmatclub.com/forum/who-says-you-need-a-149706.html#p1201595

My GMAT Journey : http://gmatclub.com/forum/end-of-my-gmat-journey-149328.html#p1197992

Kudos [?]: 72 [0], given: 562

Re: M22-04   [#permalink] 24 Feb 2013, 05:09
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# M22-04

Moderator: Bunuel

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