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Molly purchased Brand A binders at $8.00 apiece and Brand B binders at

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Molly purchased Brand A binders at $8.00 apiece and Brand B binders at  [#permalink]

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New post 23 Feb 2017, 04:47
1
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A
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Difficulty:

  5% (low)

Question Stats:

89% (01:53) correct 11% (02:47) wrong based on 76 sessions

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Molly purchased Brand A binders at $8.00 apiece and Brand B binders at $5.60 apiece. If she bought a total of 12 binders for $84.00, how many Brand A binders did she buy?

○A○ 2
○B○ 5
○C○ 6
○D○ 7
○E○ 10
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Re: Molly purchased Brand A binders at $8.00 apiece and Brand B binders at  [#permalink]

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New post 23 Feb 2017, 08:14
vikasp99 wrote:
Molly purchased Brand A binders at $8.00 apiece and Brand B binders at $5.60 apiece. If she bought a total of 12 binders for $84.00, how many Brand A binders did she buy?

○A○ 2
○B○ 5
○C○ 6
○D○ 7
○E○ 10


\(8a + 5.6 ( 12 - a ) = 84\)

Or, \(8a + 67.2 - 5.6a = 84\)

Or, \(2.4a = 16.8\)

Or, \(a = 7\)

Thus, answer must be (D) 7
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Re: Molly purchased Brand A binders at $8.00 apiece and Brand B binders at  [#permalink]

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New post 27 Feb 2017, 10:52
1
vikasp99 wrote:
Molly purchased Brand A binders at $8.00 apiece and Brand B binders at $5.60 apiece. If she bought a total of 12 binders for $84.00, how many Brand A binders did she buy?

○A○ 2
○B○ 5
○C○ 6
○D○ 7
○E○ 10


We are given that Molly purchased Brand A binders at $8.00 apiece and Brand B binders at $5.60 apiece and bought a total of 12 binders for $84.00. If we let the number of Brand A binders purchased = a and the number of Brand B binders purchased = b, we can setup two equations:

a + b = 12

b = 12 - a

and

8a + 5.6b = 84

80a + 56b = 840

10a + 7b = 105

We can substitute 12 - a for b in the equation 10a + 7b = 105:

10a + 7(12 - a) = 105

10a + 84 - 7a = 105

3a = 21

a = 7

Answer: D
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Re: Molly purchased Brand A binders at $8.00 apiece and Brand B binders at &nbs [#permalink] 27 Feb 2017, 10:52
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Molly purchased Brand A binders at $8.00 apiece and Brand B binders at

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