Last visit was: 03 Jun 2026, 02:32 It is currently 03 Jun 2026, 02:32
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
kevincan
User avatar
GMAT Instructor
Joined: 04 Jul 2006
Last visit: 03 Jun 2026
Posts: 1,860
Own Kudos:
Given Kudos: 234
GRE 1: Q170 V170
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
GRE 1: Q170 V170
Posts: 1,860
Kudos: 2,798
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
karlfurt
Joined: 02 Mar 2006
Last visit: 16 May 2008
Posts: 346
Own Kudos:
Location: France
Posts: 346
Kudos: 585
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
tennis1ball
Joined: 25 Jun 2006
Last visit: 18 Mar 2008
Posts: 650
Own Kudos:
Posts: 650
Kudos: 1,018
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Hermione
Joined: 23 May 2005
Last visit: 16 Dec 2006
Posts: 139
Own Kudos:
Location: Sing/ HK
Posts: 139
Kudos: 277
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Just to give you guys my breakdown for (1) ...

If n=1, then n!=1 and k =0 --> (0-5)^2 > 0 holds true

The only time (k-5)^2>0 will not be true is if k=5. And k will be = to 5 when we have a multiple of 100,000 or 10^5 (ending in five 0s). 100,000 = (5^5) * (2^5)

But I'm not too sure if (1) is SUFFICIENT. I'm thinking if you get the factorial of a bigger number like 40 or 50 (although i didnt compute for this), you might get a number ending in five zeros. Wasn't patient enough to compute tho... Might be too cumbersome for an actual GMAT question so I would go with D. But I think B is a possibility...
User avatar
FN
User avatar
Current Student
Joined: 28 Dec 2004
Last visit: 07 May 2012
Posts: 1,575
Own Kudos:
Given Kudos: 2
Location: New York City
Concentration: Social Enterprise
Schools:Wharton'11 HBS'12
Posts: 1,575
Kudos: 688
Kudos
Add Kudos
Bookmarks
Bookmark this Post
(1) how can this be sufficient? if K=5 then (k-5)^2=0?

not sure i understand your rational.can you please elaborate


karlfurt
D

1. n! finishes with five 0 if contains an integer multiplied by 10^5.
10=2.5 so n! has to contain 5 multiples of 2 and 5 multiples of 5.
so n=1.2.3.4.5.6.7.8.9.10....15....20= 20! contains four '5' and more than five '2'. The next possible integer is 25! which contains six '5'.
So there is no n! finishing with five '0'.

SUFFICIENT

(2) There are k prime numbers less than 10n
if n=1 then 10 contains 4 prime numbers.
if n=2 then 20 contains 8 primes.

So again, there are no n satisfaying the condition.

SUFFICIENT
User avatar
FN
User avatar
Current Student
Joined: 28 Dec 2004
Last visit: 07 May 2012
Posts: 1,575
Own Kudos:
Given Kudos: 2
Location: New York City
Concentration: Social Enterprise
Schools:Wharton'11 HBS'12
Posts: 1,575
Kudos: 688
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Oh dang!..X&Y good work...i just saw your working :(

I am soo out of touch ....with GMAT..



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Data Sufficiency (DS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderator:
Math Expert
111042 posts