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ritula
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ritula
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T must be second is fine. But C says it must be either second or third. How can it be third?
atletikos
IMO C

Info: C>B, C>T,T>B
T must be the second
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B seems to be the answer, however, I am not sure what "fourth or better" means.
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ritula
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OA is C
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ugimba
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hmm... C?? I go with D though .... can some one explain why D is wrong?

C > h > b
t>h

this is how I drew my logic from.
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How come C, then statement will be false, since nobody finishes in between Cold Molasses and Three-Leg Charlie?
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What is the OE?
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Rice
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I think the OA is C.

B is false, because it states that there are 4 or less horses. However, there is no information about the number of horses in the argument. For example, if the quant is 6, B is wrong.

C is correct. Even though the argument assumes that Three-Leg Charlie could come third, it still does not refute that Three-Leg Charlie could come second.

C is the only answer
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I think it shud be D

there can be two possibilities

B(all horses) C T
or
B(all horses) T C

I don t sees how T can be at the third place

therefore rule out C

Plz comment on my approach
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samlosco
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C is the only choice

ritula
No horse finished ahead of Cold Molasses,

So CM finished first, rule out A

Quote:
horse finished behind Bag O'Bones.

BoB finished last, rule out B & E

Quote:
Also, no horse finished between Cold Molasses and Three-Leg Charlie. Therefore (assume no ties):

If CM is 1st, TLC m/b 2nd. Rule out D, leaving only C



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