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On a certain week, 950 visitors chose one of weekdays from Monday thro
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28 Apr 2021, 03:30
28 Apr 2021, 03:30
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Difficulty:
95%
(hard)
Question Stats:
41% (02:28) correct
59%
(02:15)
wrong
based on 110
sessions
On a certain week, 950 visitors chose one of weekdays from Monday through Sunday to visit a pagoda. If twice as many visitors chose Monday than Tuesday, did at least 100 visitors choose Sunday?
(1) None of the weekdays was chosen by more than 150 visitors.
(2) None of the weekdays was chosen by fewer than 75 visitors.
(1) None of the weekdays was chosen by more than 150 visitors.
(2) None of the weekdays was chosen by fewer than 75 visitors.
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Joined: 02 Jul 2017
Posts: 644
Given Kudos: 333
Location: India
Concentration: Strategy, Technology
GMAT 1: 730 Q50 V39
GMAT 2: 710 Q50 V36
Re: On a certain week, 950 visitors chose one of weekdays from Monday thro
[#permalink]
28 Apr 2021, 04:23
28 Apr 2021, 04:23
Bunuel wrote:
On a certain week, 950 visitors chose one of weekdays from Monday through Sunday to visit a pagoda. If twice as many visitors chose Monday than Tuesday, did at least 100 visitors choose Sunday?
(1) None of the weekdays was chosen by more than 150 visitors.
(2) None of the weekdays was chosen by fewer than 75 visitors.
(1) None of the weekdays was chosen by more than 150 visitors.
(2) None of the weekdays was chosen by fewer than 75 visitors.
Statement (1) None of the weekdays was chosen by more than 150 visitors.
Still 800 visitors remain, we cant say
Not sufficient
statement (2) None of the weekdays was chosen by fewer than 75 visitors.
Not sufficient
combined :
No more information- Not sufficient
E is the answer IMO
Re: On a certain week, 950 visitors chose one of weekdays from Monday thro
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28 Apr 2021, 05:24
28 Apr 2021, 05:24
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this is a tad bit tricky
there are 7 days and 950 visitors
lets say that the no of people per days are denoted by the following:
m,t,w,th,f,sa,su
so m+t+w+th+f+sa+su = 950
we know m = 2t
1) we know max value for any day is 150
we need to maximise all days and minimize Sunday
let m = 150
therefore t = 75
that leaves 725 days for the remaining 5 days , which comes to 145 days on average.
wed = 145
thu = 145
fri = 145
sat = 145
sun = 145
now even if we max out all the other days apart from sunday we are still left with 125 days for sunday which is greater than 100. SUFF
2) we know that minimum is 75 per day
minimise sunday will give us 75 for sunday. by default all days will have 75 days. since we cant figure out the distribution for the remainig people as there is no max cap it is insuff.
HENCE A
there are 7 days and 950 visitors
lets say that the no of people per days are denoted by the following:
m,t,w,th,f,sa,su
so m+t+w+th+f+sa+su = 950
we know m = 2t
1) we know max value for any day is 150
we need to maximise all days and minimize Sunday
let m = 150
therefore t = 75
that leaves 725 days for the remaining 5 days , which comes to 145 days on average.
wed = 145
thu = 145
fri = 145
sat = 145
sun = 145
now even if we max out all the other days apart from sunday we are still left with 125 days for sunday which is greater than 100. SUFF
2) we know that minimum is 75 per day
minimise sunday will give us 75 for sunday. by default all days will have 75 days. since we cant figure out the distribution for the remainig people as there is no max cap it is insuff.
HENCE A
