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# On the xy-coordinate plane, all of the following xy-coordinate points

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Re: On the xy-coordinate plane, all of the following xy-coordinate points [#permalink]
Bunuel wrote:
On the xy-coordinate plane, all of the following xy-coordinate points lie on the circumference of a circle whose radius is 10 and whose center lies at the (x,y) point (-1,0) EXCEPT:

A. $$(–6, –7)$$

B. $$(–2, 3\sqrt{11})$$

C. $$(–1, –10)$$

D. $$(7, 6)$$

E. $$(1, -4\sqrt{6})$$

Solution:

Using the center of the circle (-1, 0) and the radius of 10, we can create the equation of circle as follows:

(x - (-1))^2 + (y - 0)^2 = 10^2

(x + 1)^2 + y^2 = 100

We see that (-6, -7) cannot be a point on the circumference of the circle since (-6 + 1)^2 + (-7)^2 = 25 + 49 = 74, which is not equal to 100.

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Re: On the xy-coordinate plane, all of the following xy-coordinate points [#permalink]
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Re: On the xy-coordinate plane, all of the following xy-coordinate points [#permalink]
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