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Re: On the xy-coordinate plane, all of the following xy-coordinate points [#permalink]
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Bunuel wrote:
On the xy-coordinate plane, all of the following xy-coordinate points lie on the circumference of a circle whose radius is 10 and whose center lies at the (x,y) point (-1,0) EXCEPT:

A. \((–6, –7)\)

B. \((–2, 3\sqrt{11})\)

C. \((–1, –10)\)

D. \((7, 6)\)

E. \((1, -4\sqrt{6})\)

Solution:

Using the center of the circle (-1, 0) and the radius of 10, we can create the equation of circle as follows:

(x - (-1))^2 + (y - 0)^2 = 10^2

(x + 1)^2 + y^2 = 100

We see that (-6, -7) cannot be a point on the circumference of the circle since (-6 + 1)^2 + (-7)^2 = 25 + 49 = 74, which is not equal to 100.

Answer: A
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Re: On the xy-coordinate plane, all of the following xy-coordinate points [#permalink]
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Re: On the xy-coordinate plane, all of the following xy-coordinate points [#permalink]
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