alokgupta1009 wrote:

Hi,

Need your guidance for below qq.

p and m are positive integers, and p is a prime number. If x^2-mx+p=0 has a positive interger solution what is the value of (m-p)?

Thanks in advance !!

In any quadratic equation \(ax^2 + bx + c = 0\), the relationship between

b and

c is that

b is the sum of the factors of

c*a.

In \(x^2 - mx + p = 0\), we know

-m is the sum of the factors of

p, and we also know that

p is the prime number that means it has only two factors,

p and

1So -m = -p -1 -------> m - p = 1

Hope that helps

I didn't understand the explanation. Could you elaborate and give a numerical example?