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Re: disagree with OA [#permalink]
plz what is the OA
I agree that st 1 NOT SUFFICIENT


ST2
x^2 <1
x<sq root of 1
x<- sq root of 1
hence x<-1
x <+1
then i am stuck
can anyone correct me thanks
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Re: disagree with OA [#permalink]
Hey

this is B....


|x-6| >5?

1) x is an integer than x=4

|4-6|=2 which is <5

x can be 20

|20-6|= 14 which is > 5

insuff

2)

X^2<1

then X is a fraction

say X is 1/2

|1/2-6| = 5.5 which is >5

or X could be 0

|0-6| = 6 which is > 5...

so either way we can that (2) is always sufficient...it is always >5

B it is...
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Re: disagree with OA [#permalink]
B

x>11 or x<1

with x^2 < 1, for sure x < 1
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Re: disagree with OA [#permalink]
mandy wrote:
plz what is the OA
I agree that st 1 NOT SUFFICIENT


ST2
x^2 <1
x<sq root of 1
x<- sq root of 1
hence x<-1
x <+1
then i am stuck
can anyone correct me thanks


so x should be b/w -1 and 1.
Then for any such value | x - 5 | > 6

HMTG.
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Re: disagree with OA [#permalink]
mirhaque wrote:
disagree with OA


However, i answerd B as the OA, the question is poorly worded. suppose if statement ii is not sufficient to answer the question, statements i and ii jointly cannot answer the question because these statement contradict each other.



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