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What is the probability of rolling two normal six-sided dice and getti

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Bunuel
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What is the probability of rolling two normal six-sided dice and getti [#permalink] New post   08 Dec 2014, 06:16
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Tough and Tricky questions: Probability.



What is the probability of rolling two normal six-sided dice and getting exactly one six?

A) 1/36
B) 1/6
C) 5/18
D) 11/36
E) 1/3

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C
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JJo
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Re: What is the probability of rolling two normal six-sided dice and getti [#permalink] New post   08 Dec 2014, 21:01
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What is the probability of rolling two normal six-sided dice and getting exactly one six?

We can get six either on dice 1 or on dice 2 so:
prob(of getting six) = 1/6
prob(of not getting six) = 5/6

prob(exactly one six) = (six on dice 1 and some other no. on dice 2) or (six on dice 2 and some other no. on dice 1)
= (1/6 * 5/6) + (1/6 * 5/6)
= 5/36 + 5/36
= 5/18

Ans. C) 5/18
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Re: What is the probability of rolling two normal six-sided dice and getti [#permalink] New post   08 Dec 2014, 06:47
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What is the probability of rolling two normal six-sided dice and getting exactly one six?

A) 1/36
B) 1/6
C) 5/18
D) 11/36
E) 1/3

Possible pairs having exactly one six are (1,6), (2,6),(3,6),(4,6),(5,6),(6,1)...(6,5) = 10 pairs
Total number of possible pairs = 6*6 = 36

Therefore, probability of getting exactly one six = \(\frac{10}{36} = \frac{5}{18}\)

Answer: C
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Re: What is the probability of rolling two normal six-sided dice and getti [#permalink] New post   09 Dec 2014, 06:45
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(1/6)*(5/6)*2! = 5/18
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Re: What is the probability of rolling two normal six-sided dice and getti [#permalink] New post   12 May 2020, 10:34
What is the probability of rolling two normal six-sided dice and getting exactly one six?

A) 1/36
B) 1/6
C) 5/18
D) 11/36
E) 1/3

Number of outcomes/ Dice = 6, Total outcomes = 6^2 = 36

For getting exactly one SIX, the possibilities are like below -

(1,6)
(2,6)
.
.
(5,6)
(6,1)
(6,2)
.
.
(6,5) ............... total 10

Thus P(A) = 10/36 = 5/18 (Answer-C)
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Re: What is the probability of rolling two normal six-sided dice and getti [#permalink] New post   08 Oct 2022, 11:26
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We need to find What is the probability of rolling two normal six-sided dice and getting exactly one six?

As we are rolling two dice => Number of cases = \(6^2\) = 36

Now to get exactly one 6 we can get it in the first roll or the second roll.

Getting 6 in the first roll and not getting two sixes we will have 5 cases
(6,1), (6,2), (6,3), (6,4), (6,5)

Getting 6 in the second roll and not getting two sixes we will have 5 cases
(1,6), (2,6), (3,6), (4,6), (5,6)

=> 10 cases

=> Probability of getting exactly one six = \(\frac{10}{36}\) = \(\frac{5}{18}\)

So, Answer will be C
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

GMAT Club Bot
gmatclubot
Re: What is the probability of rolling two normal six-sided dice and getti [#permalink]
08 Oct 2022, 11:26
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