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In the figure above, the area of square PQRS is 64. What is the area
[#permalink]
19 Sep 2017, 23:34
19 Sep 2017, 23:34
Expert Reply
Show timer
00:00
A
B
C
D
E
Difficulty:
5%
(low)
Question Stats:
91% (00:55) correct
9%
(01:16)
wrong
based on 68
sessions
In the figure above, the area of square PQRS is 64. What is the area of ∆ QRT?
(A) 48
(B) 32
(C) 24
(D) 16
(E) 8
Attachment:
2017-09-20_1018_001.png [ 5.84 KiB | Viewed 4369 times ]
Re: In the figure above, the area of square PQRS is 64. What is the area
[#permalink]
20 Sep 2017, 00:59
20 Sep 2017, 00:59
Area of square PQRS = 64
Area of triangle QRT = (1/2) * b * h = (1/2) * QR * QP
Since QR * QP = side of the square * side of the square = area of the square PQRS = 64
Therefore, area of triangle QRT = (1/2) * 64 = 32
Answer is B.
Area of triangle QRT = (1/2) * b * h = (1/2) * QR * QP
Since QR * QP = side of the square * side of the square = area of the square PQRS = 64
Therefore, area of triangle QRT = (1/2) * 64 = 32
Answer is B.
In the figure above, the area of square PQRS is 64. What is the area
[#permalink]
20 Sep 2017, 03:23
20 Sep 2017, 03:23
Expert Reply
The location of point T is not defined. So it can be any point on PS. Just think of it as a point almost overlapping with S. Then area of PTR would be very close to 32 i.e. half of 64.
Since T could be such a point, the area of every such triangle must be 32 only.
Tip: In PS questions, try to make the figure as symmetrical as you can under the given constraints, to get the answer quickly. Do just the opposite for DS questions.
Since T could be such a point, the area of every such triangle must be 32 only.
Tip: In PS questions, try to make the figure as symmetrical as you can under the given constraints, to get the answer quickly. Do just the opposite for DS questions.
